47. The crystal structure of diamond is fcc, and the atom coordinates in the unit cell are (0, 0, 0), (†, £,0), (눈,0, 1), (0, 1, v), (1, 1, 4), (금, , 3), (, 국, 4). and (, , ). The lattice parameter is a = 3.57 Å. What is the C-C bond distance in diamond?

University Physics Volume 3
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Chapter9: Condensed Matter Physics
Section: Chapter Questions
Problem 13CQ: The NaCl crystal structure is FCC. The equilibrium spacing is r0=0.282nm. If each ion occupies a...
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47. The crystal structure of diamond is fcc, and the atom
coordinates in the unit cell are (0, 0, 0), , 1,0),
4),(4,去,)、(,
(1,0, t), (0, 1,v), (4.1, 4). (금, 4. 3), (, , 8).
and (, , ). The lattice parameter is a = 3.57 Å. What
4 9
%3D
4 2
is the C-C bond distance in diamond?
Transcribed Image Text:47. The crystal structure of diamond is fcc, and the atom coordinates in the unit cell are (0, 0, 0), , 1,0), 4),(4,去,)、(, (1,0, t), (0, 1,v), (4.1, 4). (금, 4. 3), (, , 8). and (, , ). The lattice parameter is a = 3.57 Å. What 4 9 %3D 4 2 is the C-C bond distance in diamond?
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