4(A) The transistor in the circuit shown in figure 6 is so biased that the DC collector current Ic is 1 mA and supply Ve is 5V. The network components have the following values Rc= 2 KN, Rs=1.4 KN, RE=100 2, The transistor has specifications, current gain is 100, and assume base spreading resistance is 100 N and VT = 26 mV. The readings were taken on room temperature. Calculate: (i) Voltage gain, (ii) Evaluate the input resistance R; for two cases at a frequency of 10 KHz, a. CE bypass capacitor across Rg is 25 uF, b. Bypass capacitor is removed leaving RE unbypassed. Vcc = +5V Rc R, (2) Vs RE CE

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4(A) The transistor in the circuit shown in figure 6 is so biased that the DC collector current Ic is 1
mA and supply Vee is 5V. The network components have the following values Rc= 2 KN, Rs=1.4
KN, RE=100 2, The transistor has specifications, current gain is 100, and assume base spreading
resistance is 100 and VT = 26 mV. The readings were taken on room temperature. Calculate:
(i) Voltage gain,
(ii) Evaluate the input resistance R; for two cases at a frequency of 10 KHz,
a. CE bypass capacitor across Rg is 25 µF,
b. Bypass capacitor is removed leaving RE unbypassed.
Vcc = +5V
Rc
R5
Vs
RE
CE
4(B) The lower cutoff frequency of first stage of the amplifier is 100 Hz and that of second stage is
200 Hz. Similarly, the upper cutoff frequency of first stage is 140 KHz and that of second stage is
100 KHz. Find out the overall lower and upper cutoff frequencies if the two stages are cascaded.
Transcribed Image Text:4(A) The transistor in the circuit shown in figure 6 is so biased that the DC collector current Ic is 1 mA and supply Vee is 5V. The network components have the following values Rc= 2 KN, Rs=1.4 KN, RE=100 2, The transistor has specifications, current gain is 100, and assume base spreading resistance is 100 and VT = 26 mV. The readings were taken on room temperature. Calculate: (i) Voltage gain, (ii) Evaluate the input resistance R; for two cases at a frequency of 10 KHz, a. CE bypass capacitor across Rg is 25 µF, b. Bypass capacitor is removed leaving RE unbypassed. Vcc = +5V Rc R5 Vs RE CE 4(B) The lower cutoff frequency of first stage of the amplifier is 100 Hz and that of second stage is 200 Hz. Similarly, the upper cutoff frequency of first stage is 140 KHz and that of second stage is 100 KHz. Find out the overall lower and upper cutoff frequencies if the two stages are cascaded.
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