4NH3 + 50₂ → 4NO + 6H₂0 Given: 2NH3 → N₂ + 3H₂ AH = +92 kJ 2H₂O → 2H₂ + O₂ AH = +572 kJ N₂0₂ + 2NO AH = -180 kJ

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Chapter8: Thermochemistry
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4NH3 + 50₂ → 4NO + 6H₂0
Given: 2NH3 → N₂ + 3H₂ AH = +92 kJ
2H₂O → 2H₂ + O₂ AH = +572 kJ
N₂0₂ + 2NO AH = -180 kJ
Transcribed Image Text:4NH3 + 50₂ → 4NO + 6H₂0 Given: 2NH3 → N₂ + 3H₂ AH = +92 kJ 2H₂O → 2H₂ + O₂ AH = +572 kJ N₂0₂ + 2NO AH = -180 kJ
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