Correct answers First mRNA base (5' end)コCAGUUUUUUCUUATUUGCUUTCUCCUACUGPheGUUGUCGUAGUGLeuLeuAUUTAUC lleAUAAUGMet orstartValSecond mRNA baseCAUCUUCCUCAUCGCCUCCCCCACCGACUTACCACAACGGCUGCCGCAGCGSerProThrAlaUAUTyrUACUAA StopUAG StopCAUCACCAACAGAAUAACAAAAAGGAUGACGAATGAGHisGinAsnLysGGluUGUCysUGCUGA StopUGG TrpCGUCGCCGACGGAGUTAGCAGAAGGGGUAsp GGCGGAGGGArgSerArgGlyUCAGUO.GUCAGUCThird mRNA base (3' end)5' AGGCCTAAGTTCCCTCACACACACAGGG 3'3¹ TCCGGATTCAAGGGAGTGTGTGTGTGCCC 5' B 5' AGGCCTAAGTTCCCTCACACACACAGGG 3′3' TCCGGATTCAAGGGAGTGTGTGTGTGCCC 5' Ba mutation in an exon can change the amino acid structure of a proteinthe associated mRNA would read 5' AGG CCT AAG TTC CCT CAC ACA CAC AGG A 3'This piece of DNA will produce a protein with 9 Amino acidsthe associated mRNA would read 3' AGG CCT AAG TTC CCT CAC ACA CAC AGG A 5'the primary structure of a protein is directly related to the sequence of amino acidsLetter A = The Template strandThere is a stop codon in the mRNA but there is not a start codonthe start codon is the 3rd codon

Genes are hereditary structures on genetic material. These control some specific particular traits.…

5' AGGCC TAAGTTCCCTCACACACACAGGG 3' 3¹ TCCGGATTCAAGGGAGTGTGTGTGTGCCC 5' B a mutation in an exon can change the amino acid structure of a protein the associated mRNA would read 5' AGG CCT AAG TTC CCT CAC ACA CAC AGG A 3' This piece of DNA will produce a protein with 9 Amino acids the associated mRNA would read 3' AGG CCT AAG TTC CCT CAC ACA CAC AGG A 5' the primary structure of a protein is directly related to the sequence of amino acids Letter A = The Template strand There is a stop codon in the mRNA but there is not a start codon the start codon is the 3rd codon

5' AGGCC TAAGTTCCCTCACACACACAGGG 3' 3¹ TCCGGATTCAAGGGAGTGTGTGTGTGCCC 5' B a mutation in an exon can change the amino acid structure of a protein the associated mRNA would read 5' AGG CCT AAG TTC CCT CAC ACA CAC AGG A 3' This piece of DNA will produce a protein with 9 Amino acids the associated mRNA would read 3' AGG CCT AAG TTC CCT CAC ACA CAC AGG A 5' the primary structure of a protein is directly related to the sequence of amino acids Letter A = The Template strand There is a stop codon in the mRNA but there is not a start codon the start codon is the 3rd codon

Biology Today and Tomorrow without Physiology (MindTap Course List)

5th Edition

ISBN:9781305117396

Author:Cecie Starr, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Christine Evers, Lisa Starr

Chapter7: Gene Expression And Control

Section: Chapter Questions

Problem 7SQ

See similar textbooks

Similar questions

mRNA sequence of A gene Find 5’ UTR and 3’UTR of mRNA 5’ AAACUGUGACUGAACCUCAAACCCCAAACCAGCCCGAGGAGAACCACAUUCUCCCAGGGA CCCAGGGCGGGCCGUGACCCCUGCGGCGGAGAAGCCUUGGAUAUUUCCACUUCAGAAGCCUACUGGGGAAGGCUGAGGGGUCCCAGCUCCCCACGCUGGCUGCUGUGCAGAUGCUGGACGACAGAGCCAGGAGGGAGGCCGCCAAGAAGGAGAAGGUAGAGCAGAUCCUGGCAGAGUUCCAGCUGCAGGAGGAGGACCUGAAGAAGGUGAUGAGACGGAUGCAGAAGGAGAUGGACCGCGGCCUGAGGUAGAAGCCGCUGGGGCUUGGGGCU-3’
mRNA sequence of A gene If we have the following mutations, find the type of the mutation (silent or missense or nonsense?) 17CàU 36GàA 49GàU 115AàC 5’ AAACUGUGACUGAACCUCAAACCCCAAACCAGCCCGAGGAGAACCACAUUCUCCCAGGGA CCCAGGGCGGGCCGUGACCCCUGCGGCGGAGAAGCCUUGGAUAUUUCCACUUCAGAAGCC UACUGGGGAAGGCUGAGGGGUCCCAGCUCCCCACGCUGGCUGCUGUGCAGAUGCUGGACG ACAGAGCCAGGAGGGAGGCCGCCAAGAAGGAGAAGGUAGAGCAGAUCCUGGCAGAGUUCCAGC UGCAGGAGGAGGACCUGAAGAAGGUGAUGAGACGGAUGCAGAAGGAGAUGGACCGCGGCCUGA GGUAGAAGCCGCUGGGGCUUGGGGCU-3’
Below is a short segment of DNA molecule. transcribed the DNA codon into mRNA. TACCATGAGAATTGTGGTCACCTTTTT ATGGTACTCTTAACACCAGTGGAAAAA
Translate the mRNA into a protein using the genetic code. (Amino acid chain.) Sequence ATCTTCCCTCCTAAACGTTCAACCGGTTCTTAATCCGCCGCCAGGGCCCCGCCCCTCAGAAGTTGGTSequence BTCAGACGTTTTTGCCCCGTAACAACTTGTTACAACATGGTCATAAACGTCAGAGATGGTC AATCTCTTAATGACTSequence CTACAAACATGTAAACACACCCTCAGTGGACCAACTCCGCAACATAAACCAAACACCGCTC GCGCCGAAAAAGATATGG
Transcribe the DNA into mRNA. Sequence ATCTTCCCTCCTAAACGTTCAACCGGTTCTTAATCCGCCGCCAGGGCCCCGCCCCTCAGAAGTTGGTSequence BTCAGACGTTTTTGCCCCGTAACAACTTGTTACAACATGGTCATAAACGTCAGAGATGGTCAATCTCTTAATGACTSequence CTACAAACATGTAAACACACCCTCAGTGGACCAACTCCGCAACATAAACCAAACACCGCTCGCGCCGAAAAAGATATGG
TACTCACCCCGTATTACGTTT What’s the MRNA Protein Phenotype
mRNA sequence of A gene Write the amino acid sequence of the gene A. 5’ AAACUGUGACUGAACCUCAAACCCCAAACCAGCCCGAGGAGAACCACAUUCUCCCAGGGA CCCAGGGCGGGCCGUGACCCCUGCGGCGGAGAAGCCUUGGAUAUUUCCACUUCAGAAGCCUACUGGGGAAGGCUGAGGGGUCCCAGCUCCCCACGCUGGCUGCUGUGCAGAUGCUGGACGACAGAGCCAGGAGGGAGGCCGCCAAGAAGGAGAAGGUAGAGCAGAUCCUGGCAGAGUUCCAGCUGCAGGAGGAGGACCUGAAGAAGGUGAUGAGACGGAUGCAGAAGGAGAUGGACCGCGGCCUGAGGUAGAAGCCGCUGGGGCUUGGGGCU-3’
Place sequences a, b and c into the correct order based on start and stop codons. Sequence ATCTTCCCTCCTAAACGTTCAACCGGTTCTTAATCCGCCGCCAGGGCCCCGCCCCTCAGAAGTTGGTSequence B TCAGACGTTTTTGCCCCGTAACAACTTGTTACAACATGGTCATAAACGTCAGAGATGGTC AATCTCTTAATGACTSequence CTACAAACATGTAAACACACCCTCAGTGGACCAACTCCGCAACATAAACCAAACACCGCTC GCGCCGAAAAAGATATGG
3’-TCTTCGTGAGATGATATAAGAGTTATCCAGGTACCGGTAAACTGG-5’ 5’-AGAAGCACTCTACTATATTCTCAATAGGTCCATGGCCATTTGACC-3’ Write down the mRNA transcript from DNA above.
Below is the CODING sequence of a gene. An A is inserted at position 131. Insert the variant and write the mature mRNA sequence. Then write the amino acid sequence of the resulting transcript. AGAGCTACCAGCTTTAGCGGGATATAAACACACTTATCCTACTATCCCTA 51 TCTTCCCCCAAAGAGGGATCATGCCGTCGACGGCCAAACCGATCGAGCGG 101 AGGTTAAGGGCCATTGGAAAAGGACACTCTGTACGACTAAGAAAATAGC 151 AGCGACTGAGCTGAACGCTACGGGGGGGGGGGTATATACCCCCCCCCCCC 201 CCAGCTACGAGCGACTTTTTATTTTTTTTTTTTATTTTTTTTCTTTTTTA 251 TTTTTTTTGTTTTTTTTTTTCGCGACTACAGAGACTTCTAGCGATCGACG 301 AGCTAGCTAGCGCGGCATCGGACGCGATCGCGATCCTAGACTCTACGAT
RNA sequence. Pls help
Complete the complementary strand: mRNA transcription ATTCGAGGCTAA