5) Calculate E cel at 313K for the concentration cell described below. Both electrodes are made or Mg. On the left side of the cell there is a solution of 0.10 M Mg(NO3)2. On the right side of the cell a saturated solution of MgF2 is prepared by adding 1.00 g of solid of MgF2 to 100.0 mL of pure water. Because Ksp for MgF2 is small (K, for MgF2=64 x 10"), the concentration of Mg²+ on the right side of the cell is much less than 0.10 M. Mg2+ + 2e Mg E° = -2.37 V Voltmeter Porous Mg Barrier Mg Saturated MgF2 0.10 M Mg(NO3)2

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Chapter18: Electrochemistry
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5) Calculate E cell at 313K for the concentration cell described below. Both electrodes
are made or Mg. On the left side of the cell there is a solution of 0.10M Mg(NO3)2. On the
right side of the cell a saturated solution of MgF2 is prepared by adding 1.00 g of solid of
MgF2 to 100.0 mL of pure water. Because Ksp for MgF2 is small (Kp for MgF2=64 x 10"),
the concentration of Mg2+ on the right side of the cell is much less than 0.10 M.
%3D
Mg2+ + 2e → Mg
E° = -2.37 V
Voltmeter
Porous
Mg
Barrier
Mg
Saturated MgF2
0.10 M Mg(NO3)2
Transcribed Image Text:5 5) Calculate E cell at 313K for the concentration cell described below. Both electrodes are made or Mg. On the left side of the cell there is a solution of 0.10M Mg(NO3)2. On the right side of the cell a saturated solution of MgF2 is prepared by adding 1.00 g of solid of MgF2 to 100.0 mL of pure water. Because Ksp for MgF2 is small (Kp for MgF2=64 x 10"), the concentration of Mg2+ on the right side of the cell is much less than 0.10 M. %3D Mg2+ + 2e → Mg E° = -2.37 V Voltmeter Porous Mg Barrier Mg Saturated MgF2 0.10 M Mg(NO3)2
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