5 partition_list (head) This is a little like split_list() from the Short problem, except that, instead of splitting the list into two by cutting it into the middle, you will now build two lists to return, using alternate values. The first value in the input list should be returned at the head of the first new list; the second value should be the head of the second list. Keep on alternating from there, putting one new value on the first list, and one on the second. (But remember that the length of the input list might be odd.) Example Suppose you have the following input list: 10 - 13 -> -1 -> 1000 - 0 It should return the following two lists: 10 > 1 -> 0 13 -> 1000

5 partition_list (head) This is a little like split_list() from the Short problem, except that, instead of splitting the list into two by cutting it into the middle, you will now build two lists to return, using alternate values. The first value in the input list should be returned at the head of the first new list; the second value should be the head of the second list. Keep on alternating from there, putting one new value on the first list, and one on the second. (But remember that the length of the input list might be odd.) Example Suppose you have the following input list: 10 - 13 -> -1 -> 1000 - 0 It should return the following two lists: 10 > 1 -> 0 13 -> 1000

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

linked_list_stack_shopping_list_manager.py This is a file that includes the class of linked list based shopping list manager. This class contains such methods as init, insert_item, is_list_empty, print_item_recursive_from_top, print_items_from_top, print_item_recursive_from_bottom, print_items_from_bottom, getLastItem, removeLastItem. In addition, this class requires the inner class to hold onto data as a linked list based on Stack. DO NOT use standard python library, such as deque from the collections module. Please keep in mind the following notes for each method during implementation: Init(): initializes linked list based on Stack object to be used throughout object life. insert_item(item): inserts item at the front of the linked list based on Stack. Parameters: item name. is_list_empty (): checks if the current Stack object is empty (ex. check if head is None). print_item_recursive_from_top(currentNode): a helper method to print linked list based on Stack item recursively. Note:…
1-Let the list have a head and a tail. That is, a pointer (have a marker) to both the beginning (first Node) of the list and the last Node. What process does Tail facilitate? 2-insert(int index, int element): adds this element to the index position. For example, if index is 4, it adds this element between index 3 and 4 in the list. The size of the list has increased by one. 3-append(int elem): Adds the element to the end of the list. The size of the list has increased by one. 4-get(int index): Returns the element at the index position of the list, no change in the list. 5-remove(int index): Returns the element at the index position of the list. This element is removed from the list and the list size is reduced by one. 6-findMin(): returns the index of the smallest number in the list. 7-findMax(): returns the index of the largest number in the list. 8-search(int elem): searches elem in the list. It returns -1 when you can't find elem's index when you find it. 9-ToArray(): Return an…
1-Let the list have a head and a tail. That is, a pointer (have a marker) to both the beginning (first Node) of the list and the last Node. What process does Tail facilitate? 2-insert(int index, int element): adds this element to the index position. For example, if index is 4, it adds this element between index 3 and 4 in the list. The size of the list has increased by one. 3-append(int elem): Adds the element to the end of the list. The size of the list has increased by one. 4-get(int index): Returns the element at the index position of the list, no change in the list. 5-remove(int index): Returns the element at the index position of the list. This element is removed from the list and the list size is reduced by one. 6-findMin(): returns the index of the smallest number in the list. 7-findMax(): returns the index of the largest number in the list. 8-search(int elem): searches elem in the list. It returns -1 when you can't find elem's index when you find it. 9-ToArray(): Return an…
1-Let the list have a head and a tail. That is, a pointer (have a marker) to both the beginning (first Node) of the list and the last Node. What process does Tail facilitate? 2-insert(int index, int element): adds this element to the index position. For example, if index is 4, it adds this element between index 3 and 4 in the list. The size of the list has increased by one. 3-append(int elem): Adds the element to the end of the list. The size of the list has increased by one. 4-get(int index): Returns the element at the index position of the list, no change in the list. 5-remove(int index): Returns the element at the index position of the list. This element is removed from the list and the list size is reduced by one. 6-findMin(): returns the index of the smallest number in the list. 7-findMax(): returns the index of the largest number in the list. 8-search(int elem): searches elem in the list. It returns -1 when you can't find elem's index when you find it. 9-ToArray(): Return an…
Java Linked List Print Program I have a program with multiple linked list that has data stored from a text file. I'm using two methods 1) getData 2) printData. I have to print the contents of my linked lists in a certain format, but I don't know how . My code and desired output is below: File Data: employ1,role3,1 employ2,role2,3 employ3,role1,2 employ2,role3,1 employ1,role1,2 employ2,role2,2 Code: public void getData(){LinkedList<String> list1 = new LinkedList<String>();LinkedList<String> list2 = new LinkedList<String>();LinkedList<String> list3 = new LinkedList<String>(); String str;while(scanner.hasNextLine()){str = scanner.next();String[] sp = str.split("-");switch(sp[1]){case "employ1":list1.add(sp[0]);list1.add(sp[2]);break;case "employ2":list2.add(sp[0]);list2.add(sp[2]);break;case "employ3":list3.add(sp[0]);list3.add(sp[2]);break;} public void printACM() { ??????? } Output: role1 role2 role3 employ1 2 1 employ2 23 1 employ3…
_!?8. Problem Title: "Add Two Numb You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order, and each of their nodes contains a single digit. Add the two numbers and return the sum as a linked list. You may assume the two numbers do not contain any leading zero, except the number 0 itself..
Implement the following function using C++ remove_redundant() This method will clear out the duplicate numbers in your linked list. It is also imperative that you will use an instance of this Linked List class to hold the numbers that you have already checked and use the methods in this instance. In the example 10 -> 10 -> 20 -> 30 -> 10, calling remove_redundant() will remove the other 2 10's that occurred later, hereby making the list 10 -> 20 -> 30. Limitation: You cannot have a nested loop here nor use methods that employ loops as the performance of our linked list will suffer.
7-Write a procedure that returns the list that contains everything except for the last element of the given (nonempty) list. For example, (last-element ‘(a (b c ) (d)) ) returns (a (b c)). For example, (last-element ‘(a (b c ) (d) ) ) returns (a (b c)) . Then, Manually trace your procedure with the provided example.
2 //please write it in java This is a circular doubly linked list. It starts at the head pointer (Head). Write a function that adds a node (P) at the nth location away from the Head keeping the circle connected. For example, based on the image, the list is: C, D, B, A After calling addNthNode(Head, P, 2), the list becomes C, F, D, B, A Note that if the position is 1 then the Head should be updated. Your code should validate parameters, and handle edge cases. void addNthNode (Node Head, Node P, int position){ // your code goes here }
class MyList: # constructor def __init__(self, a): # converting array to list newList = a.tolist() # printing the list print("List is:", newList). Complete.
def bubble_up(values: list, left: int, right: int) -> None: """Bubble up through values[left: right+1], swapping items that are out of order. Note that use of this slicing notation means that items values[left], values[left + 1], values[left + 2], ..., values[right] could be modified. Precondition: left and right are valid indexes in values. >>> list_example_1 = [4, 3, 2, 1, 0] >>> bubble_up(list_example_1, 0, 3) >>> list_example_1 [3, 2, 1, 4, 0] >>> list_example_2 = [4, 3, 2, 1, 0] >>> bubble_up(list_example_2, 2, 4) >>> list_example_2 [4, 3, 1, 0, 2] """ for i in range(left, right): if values[i] > values[i + 1]: temp = values[i] values[i] = values[i + 1] values[i + 1] = temp # Use the bubble_up function as a starting point to help you complete the# bubble_down function.def bubble_down(values: list, left: int, right: int) -> None:…
class Node: def __init__(self, e, n): self.element = e self.next = n class LinkedList: def __init__(self, a): # Design the constructor based on data type of a. If 'a' is built in python list then # Creates a linked list using the values from the given array. head will refer # to the Node that contains the element from a[0] # Else Sets the value of head. head will refer # to the given LinkedList # Hint: Use the type() function to determine the data type of a self.head = None # To Do # Count the number of nodes in the list def countNode(self): # To Do # Print elements in the list def printList(self): # To Do # returns the reference of the Node at the given index. For invalid index return None. def nodeAt(self, idx): # To Do