5 X, + 3 X, + 2 X, = 11 4 X, + 8X, — 3 х, — 9 5 X, + 3 X, + 2 X = 15

College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
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Chapter8: Sequences, Series,and Probability
Section8.6: Counting Principles
Problem 5ECP: How many permutations of the letters W, X, Y, and Z are possible?
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4. Calculate how much the variables X 1, X 2 and X 3 from the simultaneous equation below:

 

5 X, + 3 X, + 2 X, = 11
4 X, + 8X, — 3 х, — 9
5 X, + 3 X, + 2 X = 15
Transcribed Image Text:5 X, + 3 X, + 2 X, = 11 4 X, + 8X, — 3 х, — 9 5 X, + 3 X, + 2 X = 15
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