Please solve this question, quickly i will rate. 5. An electric field of 800 V/m makes an angle of 20.00 with the surface vector. It has amagnitude of 0.400 m2. Find the electric flux that passes through the surface.

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Answered: 5. An electric field of B00 V/m makes…

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter6: Gauss's Law

Section: Chapter Questions

Problem 1CQ: Discuss how to orient a planar surface of area A in a uniform electric field of magnitude E0 to...

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A dosed surface with dimensions a = b= 0.400 111 and c = 0.600 in is located as shown in Figure 124.63. The left edge of the closed surface is located at position x = a. The electric field throughout the region is non- uniform and is given by E = (3.00 + 2.00x2)i N/C, where x is in meters. (a) Calculate the net electric flux leaving the closed surface. (b) What net charge enclosed by the surface?
Find the electric flux through the surface in Figure 15.28. Assume all charges in the shaded area are inside the surface. (a) (3 C)/0 (b) (3 C)/0 (c) 0 (d) (6C)/0
Discuss how to orient a planar surface of area A in a uniform electric field of magnitude E0 to obtain (a) the maximum flux and (b) the minimum flux through the area.
What is the value of electric flux (Φ) through a plane of area 2 m2 on which an electric field of 2 V/m crosses with an angle of 60o.
9. A flat sheet of paper of area 0.250 m 2 is oriented so that the normal to the sheet isat an angle of 60ﹾ to a uniform electric field of magnitude 14 N/C. Find themagnitude of the electric flux through the sheet.
An electric field of intensity 3.50 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.350 m wide and 0.700 m long if the plane is parallel to the xy-plane.
A circular surface with a radius of 0.062 m is exposed to a uniform electric field of magnitude 1.58 × 104 N/C. The electric flux through the surface is 68 N·m2/C. What is the angle between the direction of the electric field and the normal to the surface?
A uniform electric field of strength E = 334 N/C passes through a flat surface at an angle of 0.880 radians. The electric flux is 455 (N/C)·m2. What is the area of the surface?
what can you conclude about the relationship among the electric flux, electric field lines, and the charge enclosed by the surface?
A 47.0-cm-diameter circular loop is rotated in a uniform electric field until the position of maximum electric flux is found. The flux in this position is measured to be 5.94 105 N · m2/C. What is the magnitude of the electric field?
3. A solid insulating sphere of radius 0.07 m carries a total charge of 25 µC. Concentric with this sphere is a conducting spherical shell of inner radius 0.12 m and outer radius of 0.18 m and carrying a total charge of -54 µC. Find (a) the charge distribution for the insulating sphere and the conducting spherical shell, and the magnitude of the electric field at the following distances from the center of the two spheres and shell: (b) 0.05 m, (c) 0.10 m, (d) 0.15 m, and (e) 0.25 m.
47. If the electric field lines are parallel to the area, the electric flux will be? A. Minimum B. Zero C. Maximum D. One

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5. An electric field of B00 V/m makes an angle of 20.00 with the surface vector. It has a magnitude of 0.400 m2. Find the electric flux that passes through the surface.