Question
Asked Nov 19, 2019
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I was told to ask this as an advanced maths question

5. Consider
pIn(3)+1 f(, y)dx dy.
Sketch the region of integration and write an equivalent iterated integral with
the order of integration reversed. Note: The (y-1) is in the exponent of e in
the problem statement
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5. Consider pIn(3)+1 f(, y)dx dy. Sketch the region of integration and write an equivalent iterated integral with the order of integration reversed. Note: The (y-1) is in the exponent of e in the problem statement

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Expert Answer

Step 1

Given

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rin(3)+1 re- f(x, y)dxcy) 1 Here rvaries fromx tor e and y varies fromy 0 toy n(3)+1

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Step 2

The region of integration according to equation (i)

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3- 2+ dx y1log 3 y= 0

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Step 3

For equivalent iterated integral with the order of int...

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from(i take the limit of x Inx y Inx 1y.(ii) y varies from y 0 to y ln (3)+1 in equation (i) Put y In (3)+1in (ii) In x 1 n (3)+1 Inx In (3) > e'nx = e!n3 x3 Hence the limit of x willbe 1 x =- tox =3

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Advanced Math