5. Consider the shown in the figure below. Block A weighs 45.0 N and block B weighs 25.0 N. Once block B is set into downward motion, it descends at a constant speed. (a) Calculate the coefficient of kinetic friction between block A and the tabletop. (b) A cat, also of weight 45.0 N, falls asleep on top of block A. If block B is now set into downward motion, what is its acceleration (magnitude and direction)? B

Principles of Physics: A Calculus-Based Text
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Chapter5: More Applications Of Newton’s Laws
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5. Consider the shown in the figure below. Block A weighs 45.0 N and block B weighs 25.0 N. Once
block B is set into downward motion, it descends at a constant speed. (a) Calculate the coefficient
of kinetic friction between block A and the tabletop. (b) A cat, also of weight 45.0 N, falls asleep
on top of block A. If block B is now set into downward motion, what is its acceleration (magnitude
and direction)?
B
6. In the figure below. m₁ = 20.0kg and a = 53.1º. The coefficient of kinetic friction between the
block and the incline is = 0.40. What must be the mass of m₂ of the hanging block if it is to
descend 12.0 mn in the first 3.00 s?
m₁
m₂
7. Steve pushes a second stalled car with a steady force The F = 160Ni-40N) displacement of the
car is 5 = 14mi + 11mj How much work does Steve do in this case?
Transcribed Image Text:5. Consider the shown in the figure below. Block A weighs 45.0 N and block B weighs 25.0 N. Once block B is set into downward motion, it descends at a constant speed. (a) Calculate the coefficient of kinetic friction between block A and the tabletop. (b) A cat, also of weight 45.0 N, falls asleep on top of block A. If block B is now set into downward motion, what is its acceleration (magnitude and direction)? B 6. In the figure below. m₁ = 20.0kg and a = 53.1º. The coefficient of kinetic friction between the block and the incline is = 0.40. What must be the mass of m₂ of the hanging block if it is to descend 12.0 mn in the first 3.00 s? m₁ m₂ 7. Steve pushes a second stalled car with a steady force The F = 160Ni-40N) displacement of the car is 5 = 14mi + 11mj How much work does Steve do in this case?
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