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5. Measure Tinitial, water the initial temperature of the warm water, temperature of the ice. 6. Add small chunks of ice to the warm water, wiping the excess water from each of ice immediately before adding. Add the ice slowly, stirring slowly but continuo- thermometer until each chunk melts. 7. When the temperature of the mixture is as much below room temperature as the water was initially above room temperature and all the ice is melted, measure the temperature of the water (Tinn). 8. Immediately after measuring Tanal, weigh the calorimeter and water (includin; determine Manal. Linitia Data: Tm -20.0°C 19.2g 180.9g Meal %3! Meal + water = Tinitial, water 34.0°C %3D Tinitial, ice = 0°C Tinal 6.0°C %3! Minal %3D 6.5g Mjce = Minal - Mcal + water Calculations: According to the principle of the conservation of energy, the quantity of heat a the ice as it melts and then heats up to the final equilibrium temperature must the quantity of heat released by the warm water as it cools down to the final ec temperature. Note that the initial temperature of the ice may be below freezing some energy is needed to heat the ice to the freezing/melting temperature. *ehough ice to =0°C water Mathematically: (Mice)(Le)+ (Mice)(1 cal/g K)(Tinal -0° C) + (Mice)(0.5 cal/g K)(0°C- Timitial, ie- KYT 1 Te

5. Measure Tinitial, water the initial temperature of the warm water, temperature of the ice. 6. Add small chunks of ice to the warm water, wiping the excess water from each of ice immediately before adding. Add the ice slowly, stirring slowly but continuo- thermometer until each chunk melts. 7. When the temperature of the mixture is as much below room temperature as the water was initially above room temperature and all the ice is melted, measure the temperature of the water (Tinn). 8. Immediately after measuring Tanal, weigh the calorimeter and water (includin; determine Manal. Linitia Data: Tm -20.0°C 19.2g 180.9g Meal %3! Meal + water = Tinitial, water 34.0°C %3D Tinitial, ice = 0°C Tinal 6.0°C %3! Minal %3D 6.5g Mjce = Minal - Mcal + water Calculations: According to the principle of the conservation of energy, the quantity of heat a the ice as it melts and then heats up to the final equilibrium temperature must the quantity of heat released by the warm water as it cools down to the final ec temperature. Note that the initial temperature of the ice may be below freezing some energy is needed to heat the ice to the freezing/melting temperature. *ehough ice to =0°C water Mathematically: (Mice)(Le)+ (Mice)(1 cal/g K)(Tinal -0° C) + (Mice)(0.5 cal/g K)(0°C- Timitial, ie- KYT 1 Te

Inquiry into Physics
Inquiry into Physics
8th Edition
ISBN:9781337515863
Author:Ostdiek
Publisher:Ostdiek
Chapter5: Temperature And Heat
Section: Chapter Questions
Problem 6Q: (¦ Indicates a review question, which means it requires only a basic understanding of the material...
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What would be the latent heat of fusion per gram of water for this problem?
Tr Chemistry & Physics Dept. 5. Measure Tinitial,water the initial temperature of the warm water, and Timitial temperature of the ice. 6. Add small chunks of ice to the warm water, wiping the excess water from each p of ice immediately before adding. Add the ice slowly, stirring slowly but continuou thermometer until each chunk melts. 7. When the temperature of the mixture is as much below room temperature as the water was initially above room temperature and all the ice is melted, measure the f temperature of the water (Tinal). 8. Immediately after measuring Tanal, weigh the calorimeter and water (including determine Menal- Data: Tm =10.0°C 9.2g Meal = 180.9g y of the Meal + water = 34.0°C co ht h te W h er Tinitial, wuter = 0°C Tinitial, ice = Tinal = 6.0°C Minal = 18743 Mice = Minal - Meal + water= Calculations: According to the principle of the conservation of energy, the quantity of heat ab the ice as it melts and then heats up to the final equilibrium temperature must e the quantity of heat released by the warm water as it cools down to the final temperature. Note that the initial temperature of the ice may be below freezing some energy is needed to heat the ice to the freezing/melting temperature. *enough Ice to =0°C water Mathematically: (Mice)(Le) + (Mice)(1 cal/g K)(Tinal - 0° C) + (Mice)(0.5 cal/g K)(0°C - Tinitial, ice K)(Tinitial - Tfinal)
Transcribed Image Text:Tr Chemistry & Physics Dept. 5. Measure Tinitial,water the initial temperature of the warm water, and Timitial temperature of the ice. 6. Add small chunks of ice to the warm water, wiping the excess water from each p of ice immediately before adding. Add the ice slowly, stirring slowly but continuou thermometer until each chunk melts. 7. When the temperature of the mixture is as much below room temperature as the water was initially above room temperature and all the ice is melted, measure the f temperature of the water (Tinal). 8. Immediately after measuring Tanal, weigh the calorimeter and water (including determine Menal- Data: Tm =10.0°C 9.2g Meal = 180.9g y of the Meal + water = 34.0°C co ht h te W h er Tinitial, wuter = 0°C Tinitial, ice = Tinal = 6.0°C Minal = 18743 Mice = Minal - Meal + water= Calculations: According to the principle of the conservation of energy, the quantity of heat ab the ice as it melts and then heats up to the final equilibrium temperature must e the quantity of heat released by the warm water as it cools down to the final temperature. Note that the initial temperature of the ice may be below freezing some energy is needed to heat the ice to the freezing/melting temperature. *enough Ice to =0°C water Mathematically: (Mice)(Le) + (Mice)(1 cal/g K)(Tinal - 0° C) + (Mice)(0.5 cal/g K)(0°C - Tinitial, ice K)(Tinitial - Tfinal)
initial, ice Tinal = Mfinal = Mice = Mfinal - Mcal + water Calculations: According to the principle of the conservation of energy, the quantity of heat absorbed by the ice as it melts and then heats up to the final equilibrium temperature must equal the the quantity of heat released by the warm water as it cools down to the final equilibrium temperature. Note that the initial temperature of the ice may be below freezing, in which case some energy is needed to heat the ice to the freezing/melting temperature. Mathematically: (Mice)(Lf) + (Mice)(1 cal/g K)(Tfinal - 0° C) + (Mice)(0.5 cal/g K)(0°C – Tinitial, ice) = (Mwater)(1 cal/g K)(Tinitial - Tfinal) %3D
Transcribed Image Text:initial, ice Tinal = Mfinal = Mice = Mfinal - Mcal + water Calculations: According to the principle of the conservation of energy, the quantity of heat absorbed by the ice as it melts and then heats up to the final equilibrium temperature must equal the the quantity of heat released by the warm water as it cools down to the final equilibrium temperature. Note that the initial temperature of the ice may be below freezing, in which case some energy is needed to heat the ice to the freezing/melting temperature. Mathematically: (Mice)(Lf) + (Mice)(1 cal/g K)(Tfinal - 0° C) + (Mice)(0.5 cal/g K)(0°C – Tinitial, ice) = (Mwater)(1 cal/g K)(Tinitial - Tfinal) %3D
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