jxi=-k_This The convention is to choose the direction of +z so that ?Xj=kv which automatically means that is called a right handed coordinate system. This allows one to write the cross product using components as shown below. A=A;i+Ayjand B=Bzi+Byj_ The cross product in terms of the components is Assume two vectors therefore: ÄxB=A,B,(ixj)+A,B.(jxi)=(A,B,-A,B.)k Use this formula for the cross product to determine the torque due to a force (7 î + 9 ĵ ) newtons and applied at displacement (0.8 î + 1.2 ĵ ) m from the axis of rotation. What is the z-component of the torque newton-meters? Be careful, remember it matters which vector comes first.

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The convention is to choose the direction of +z so that ?Xj=kwhich automatically means that IXi=-k.
is called a right handed coordinate system. This allows one to write the cross product using components as
This
shown below.
A=Azi+Ayj;
B=Bzi+Byj_ The cross product in terms of the components is
j and
Assume two vectors
therefore:
ÄxB=A,B,(ixj)+4, B.(jxi)=(A, B,-A,B,.)k
Use this formula for the cross product to determine the torque due to a force (7 î + 9 ĵ) newtons and applied
at displacement (0.8 î + 1.2 ĵ) m from the axis of rotation. What is the z-component of the torque
in
newton-meters? Be careful, remember it matters which vector comes first.
Transcribed Image Text:The convention is to choose the direction of +z so that ?Xj=kwhich automatically means that IXi=-k. is called a right handed coordinate system. This allows one to write the cross product using components as This shown below. A=Azi+Ayj; B=Bzi+Byj_ The cross product in terms of the components is j and Assume two vectors therefore: ÄxB=A,B,(ixj)+4, B.(jxi)=(A, B,-A,B,.)k Use this formula for the cross product to determine the torque due to a force (7 î + 9 ĵ) newtons and applied at displacement (0.8 î + 1.2 ĵ) m from the axis of rotation. What is the z-component of the torque in newton-meters? Be careful, remember it matters which vector comes first.
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