5. n log? n = 0(n²) 6. n log n 20(n) n 3=
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A: Answer is given in step2.
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A: Please upvote. I am providing you the correct answer below. Please please please.
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A: Answer the above questions are as follows:
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A: True
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Q: is taken 10 times. L1: R1=0 R2=99 L2: BEQ R1,R2, L1 .... ADD R1, R1,1 JUMP L2 ....
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A: I have provided the answer in step2.
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- def makeRandomList(size): lyst = [] for count in range(size): while True: number = random.randint(1, size) if not number in lyst: lyst.append(number) break return lyst give me proper analysis of this code and Big Owhat are the values of the variables when runned? int j,kboolean mj = 1k = j++m = (++k == j++) ------------------ int x = 3if (x == 2)x= 0if (x==3)x++elsex+=2 --------------- how many times will it be looped for(int x = 0; x== 2; x++){//body of the loop}Write a java code for search number using divide and conquer with the help of the Fibbonaci numbers
- int a[10] = {0,1,2,3,4,5,6,7,8,9};int *m = &a[0];int *p = &a[5];int *q = &a[1]; p = (int) m + (int) p - (int) q; what is the value of of *pWrite a method that displays an n-by-n matrix usingthe following header:public static void printMatrix(int n)Each element is 0 or 1, which is generated randomly. Write a test programthat prompts the user to enter n and displays an n-by-n matrix. Here is asample run: Enter n: 3 ↵Enter0 1 00 0 01 1 1Given that integer array x has elements 4, 7, 3, 0, 8, what are the elements after the loop? inti;for (i = 0; i < 4; ++i) {x[i] = x[i + 1];} a. 4, 4, 7, 3, 0 b. 7, 3, 0, 8, 8 c. 7, 3, 0, 8, 4 d. Error: Invalid access JAVA
- /* segvhunt.cFind and eliminate all code that generates Segmentation Fault*/#include <stdio.h>int main() {char **s;char foo[] = "Hello World";*s = foo;printf("s is %s\n",s);s[0] = foo;printf("s[0] is %s\n",s[0]);return(0);}Add a loop over to this function that tracks how many times the sum functions is called. Also explain how the loop is working. int64_t sum(int64_t N, uint64_t A[]){ int64_t sum = 0; uint64_t indx = A[0]; for (int64_t i = 0; i < N; i++){ sum += A[indx]; indx = A[indx]; } return sum;}5. Which substitution should best be used in solving the recurrence T(n) = 5T(4n/3) + 2? Selected answer will be automatically saved. For keyboard navigation, press up/down arrow keys to select an answer. a n = (3/4)^k b n = (4/3)^k c n = (15/4)^k d n = (20/3)^k e n = (3/20)^k f n = (3/15)^k g n = 2^k h n = 3^k i n = 4^k j n = 5^k
- In Java Write an application that inputs five numbers, each between 10 and 100, inclusive. As each number is read, display it only if it’s not a duplicate of a number already read. Provide for the “worst case,” in which all five numbers are different. Use the smallest possible array to solve this problem. Display the complete set of unique values input after the user enters each new value. Rough output in screenshotvoid countSort(int arr[], int n, int exp) { intoutput[n]; inti, count[10] = { 0 }; for (i=0; i<n; i++) count[(arr[i] /exp) %10]++; for (i=1; i<10; i++) count[i] +=count[i-1]; for (i=n-1; i>=0; i--) { output[count[(arr[i] /exp) %10] -1] =arr[i]; count[(arr[i] /exp) %10]--; } for (i=0; i<n; i++) arr[i] =output[i]; } Can I get this C code in MIPS programming language?Please help me with the listed revisions for the code below. Thank you. from math import pi, sin def m_trapz(f, a, b, n=100): res = (f(a)+f(b))/2 h = (b-a)/n for k in range(1, n): res = res+f(a+h*k) da = (f(a+h)-f(a))/h db = (f(b)-f(b-h))/h return res*h - (db-da)*(h**2)/12 def f(x): return sin(x) a = 0 b = pi/2 exact = 1 print('n\tI\tError') for n in [10, 100, 1000, 10000]: I = m_trapz(f, a, b, n) print('%d\t%.4f\t%.2e' % (n, I, I-exact))