5. The field circuit of a 200,000W, 230V shunt generator is 8A when running full load at rated terminal voltage. If the combined brush and armature resistance is 0.03 ohm, solve for the electrical efficiency of the generator.
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- An A 20kW DC shunt generator having an armature circuit resistance of 0.8Ω and a field resistance of 140 Ω, generates a terminal voltage of 230V at full load. Determine the total iron, friction and windage losses if the efficiency of the generator at full load= 83%.Open circuit tests carried out on a 3.5 MVA, 4.16 kV, 60 Hz, three phase star connected synchronous generator gave the following results:If (A):1015202530EL (kV):3.54.165.76.257.95In the short circuit test a field current of 20A was needed to circulate full load current. The armature winding resistance is 1.2Ω /phase, the field winding resistance is 500 Ω and the rotational loss is 250kW. Determine the power angle, the voltage regulation and the efficiency when the generator delivers rated load at terminal voltage of 4.4 kV and at 0.8 power factor leading.Draw the power flow diagram for the generator and include all values of power flows.A 70-MVA, 69.3-kV, three-phase round-rotor synchronous generator has a synchronous reactance of 14 ohm per phase and negligible armature resistance. 1) The generator is delivering rated power at 0.87 power factor lagging at the rated terminal voltage to an infinite bus bar (Fig. 1). Determine the magnitude of the generated emf per phase and the power angle δ. 2) The generator is delivering 53.5 MW to the bus bar at the rated voltage with its field current adjusted for a generated emf of 46 kV per phase. Determine the armature current and the power factor. Is the power factor is lagging or leading? 3) Given that the generator is operating at the excitation voltage of Part (1), determine the maximum steady-state power which the machine can deliver without losing synchronism. Find the armature current corresponding to this maximum power.
- Problem: The field current of a 100-kW, 250V shunt generator is 5A when delivering power at rated terminal voltage and rated load current. The combined armature and brush resistance is 0.1 ohm. 1.)Calculate the generated power in kW. 2.)What is the electrical efficiency? * Formatt: given required solution answerA three phase, 50 Hz, 4800V, 6 pole Y-connected synchronous generator connected to an infinite bus (constant voltage at 4800V) and has synchronous reactance of 20Ω per phase and negligible armature resistance. The generator is delivering 1 MW at a power angle of 30 degrees.. Calculate the following:1. Output torque of the generator2. Excitation voltage Ea3. Armature current4. Power factor5. Reactive power deliveredA three-phase, 12-kV, 60 Hz, 6 pole wye connected synchronous generator has synchronous reactance of 15 Ω per phase and negligible armature resistance. For a given field current, the open circuit voltage is 13 kV. Determine the following:(A) Terminal Voltage b) Excitation voltage EA at maximum powerc) The maximum power developed by the generator
- A 480-V, 60-Hz, Y-Connected synchronous generator,having the synchronous reactance of 1.04 ohm andnegligible armature resistance, is operating alone. Theterminal voltage at rated field current at open circuitcondition is 480V.1. Calculate the voltage regulation1. If load current is 100A at 0.8 PF lagging2. If load current is 100A at 0.8 PF leading3. If load current is 100A at unity PF2. Calculate the real and reactive power delivered in eachcase.3. State and explain whether the voltage regulation willimprove or not if the load current is decreased to 50 Afrom 100 A at 0.8 PF lagging.A 2-MVA, 4400-V, 25-Hz, Y-connected, three-phase, synchronous generator is tested at its rated speed of 500 rpm. The open-circuit voltage and the short-circuit current are 4800 V and 260 A, respectiveΩly, when the field current is 15 A and the field voltage is 120 V. The generator is designed to have a resistive voltage drop of 5% of its rated voltage per phase.Determine the synchronous impedance. (0.48 +j10.65) ΩFind (a) the voltage regulation (52.07%)when the generator delivers the rated load at the rated voltage and unity power factor, and the efficiency (90.6) if the rotational loss is 5% of power developed.If the armature resistance of a 3-phase, 318.75 kVA, 2300-V synchronous generator is 0.35 ohms per phase, the synchronous reactance is It is 1.2 ohms. Calculate the excitation voltage and voltage regulation for the following load cases: a) Full load, back power factor of 0.8 and rated voltage. b) Full load, forward power factor of 0.6 and rated voltage.
- A three-phase Y-connected synchronous generator has rated values of 90 MVA, 15 kV, 0.6 reverse power factor, 50-Hz. Synchronous reactance 1.6 ohmsand armature resistance is neglected. According to thisa) Find the induced voltage (EA) and armature current (LA). b) Find the voltage regulation.c) If this generator was operated at 60 Hz with the same armature and field losses as at 50 Hz; What would be the voltage, apparent power and reactance of the generatorA 150-kW 250-volt compound generator is connected long shunt. If the shunt field resistance is 20 ohms, what is the series field-current at full load? (Ans.: 612.5 A) write diagram, given, etcEMachines A 100 MVA, 11.5 kV 0.8 pf lagging 50-Hz two pole Y-connected synchronous generator has a per-unitsynchronous reactance of 0.8 and per-unit armature resistance of 0.012. A. What is its synchronous reactance and armature resistance in ohms?B. What is the magnitude of the internal generated voltage at the rated conditions? What is its torque angleat these conditions?C. Ignoring losses in this generator, what torque must be applied to its shaft by the prime mover at fullload?