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- In theory, most metals should easily corrode in air. Why? A group of metals called the noble metals are relatively difficult to corrode in air. Some noble metals include gold, platinum, and silver. Reference Table 17-1 to come up with a possible reason why the noble metals are relatively difficult to corrode.Which of the following set of conditions will accompish the following reaction? A) Na, NH3(I), -33oC B) H2, Pd/C C) H2, Lindlar's catalyst D) H2O, H2SO4Which generalized equation represents a double replacement reaction? a- AB--->A+B b-AB+CD--->AD+CD c- A+B--->AB d-A+BC--->B+AC
- How many grams of O 2 are required to burn 46.0 grams of C 5H 12? C 5H 12 + 8O 2 --> 5CO 2 + 6H 2O with complete solutionWhat is ΔG° for the following reaction? (F = 96,500 C • mol –1) I2(s) + 2Br–(aq) → 2I–(aq) + Br2(l)Given:I2(s)(aq) + 2e– → 2I –(aq) E°= 0.53 VBr2(l) + 2e– → 2Br–(aq) E° = 1.07 VWhat type of reaction is 2AgNO3 + Cu > Be(NO3)2 +2Ag
- This is the original equation: 2NO_3^- + 3H_2 --> 2NO + 2H_2O + 2OH^- Is this the oxidation reaction: 3H_2 + 3H_2O + 6OH^- --> 9H_2O + 6e^- If so, can you reduce it to the lowest coefficients? Is this the reduction reaction: 2NO_3^- + 8H_2O + 6e- --> 2NO + 4H_2O + 8OH^- If so, can you reduce it to the lowest coefficients? This is another equation: SO_3^2-+2Cu(OH)_2 --> SO_4^2-+2CuOH+H_2O I need a balanced oxidation reaction and reduction reaction, please. This is another equation: SO_3^2-+2Cu(OH)_2 --> SO_4^2-+2CuOH+H_2O I need a balanced oxidation reaction and reduction reaction, please. This is another equation: In(s) + Cr2O72−(aq) → In(OH)3(s) + Cr(OH)4−(aq) I need it balanced, and I also need a balanced oxidation reaction and the reduction reaction. This is another equation: 2Mn(OH)_2 + O_2 --> 2MnO_2 + 2H_2O I need a balanced oxidation reaction and reduction reaction, please. Thank you! Please make sure they are correct!!!What type of reaction is SeCI6 + O2 >SeO2 + 3CI2The compound diborane (B2H6) was at one time considered for use as a rocket fuel. Its combustion reaction is B2H6(g) + 3 O2(l) → 2 HBO2(g) + 2 H2O(l) The fact that HBO2, a reactive compound, was produced rather than the relatively inert B2O3 was a factor in the discontinuation of the investigation of the diborane as a fuel. What mass of liquid oxygen (LOX) would be needed to burn 234.4 g of B2H6? Answer in units of g.
- The compound diborane (B2H6) was at one time considered for use as a rocket fuel. Its combustion reaction is B2H6(g) + 3 O2(l) → 2 HBO2(g) + 2 H2O(l). The fact that HBO2, a reactive compound, was produced rather than the relatively inert B2O3 was a factor in the discontinuation of the investigation of the diborane as a fuel. What mass of liquid oxygen (LOX) would be needed to burn 234.4 g of B2H6? Answer in units of g. (part 2 of 2) What mass of HBO2 is produced from the combustion of 94.7 g of B2H6? Answer in units of g.ABS plastic is a polymer consisting of three monomer units: acrylonitrile (C₃H₃N), butadiene (C₄H₆), and styrene (C₈H₈). A sample of ABS plastic contains 11.7% N by mass. It took 1.56 g of Br₂ to react completely with a 2.00 g sample of ABS plastic. Bromine reacts 1:1 (by moles) with the butadiene units in the polymer and nothing else, so bromination is a method for determining the quantity of butadiene in the polymer. What is the percent by mass of styrene in the polymer?For Questions 11-16: Balance the following oxidation-reduction reaction in acidic conditions using the half reaction method by following the step described in each question. ??2?−27(??)+???2(??)⟶??+3(??)+??−3(??)Cr2O7−2(aq)+HNO2(aq)⟶Cr+3(aq)+NO3−(aq) Step 1: Assign the oxidation states of each ATOM in the reaction before and after the reaction takes place. Reactants: Cr = ["", "", "", "", "", "", "", "", "", "", "", "", "", "", ""] O = ["", "", "", "", "", "", "", "", "", "", "", "", "", "", ""] H = ["", "", "", "", "", "", "", "", "", "", "", "", "", "", ""] N = ["", "", "", "", "", "", "", "", "", "", "", "", "", "", ""] Products: Cr = ["", "", "", "", "", "", "", "", "", "", "", "", "", "", ""] O = ["", "", "", "", "", "",…