5. Write the position vector rA/O that points from point O to point A. Express F as a vector in terms of the unit vectors i, j, and k. A 105 1 x F = 61 N 137 40 0 Dimensions in millimeters
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- Find the value of β and P. (Disregard F1=60kN)For the area shown, determine: a) The centroidal coordinates X and Y. b) The moment of inertia about the X and Y axes (IxeIy) . c) The polar moment of inertia about the origin (Jo) . d) The moment centroidal polar of inertia (Jc).Data are as follows: P=6.2 kN, L=3.2m, d=1.25m, b=80mm, t=25, h=120mm, h1=90mm. Determine the moment of inertia about the centroidal x-axis in mm^4.
- solving equations 5 and 6 actually gives you EIθB=60.69, EIθC=-210.52A 50-m steel tape was used to measure a line and the initial pull = 5.5 kg. Pull attime of measurement = 8.0 kg. Weight of tape = 0.05 kg/m. E = 2.1 x 10^6kg/cm^2? Cross section = 0.04 sq.cm. Measured distance between two points =488.650 m, in an inclined surface having a gradient of 3%. Find the correcthorizontal distance between the two points. A. 486.456 C. 488.625 B. 490.844 D. 488.147 A rectangular lot was being measured using a 30-m metallic tape which was 6 mm too long.The recorded dimension where 70.50 m long by 37.10 m wide. What is the error in area (m^2) introduced due to the erroneous length of tape? A. 1.05 C. 0.86 B. 1.86 D. 2.02 It is required to lay out a distance of 687.78m with a 50m tape that is 0.030 m too long. Compute the distance measured with the tape to make the points the proper distance apart. A. 688.19 m C. 687.19m B. 687.37 m D. 687.94 m4. Compute the sea level distance of a line which…16. The rectangular coordinates of a particle are given in millimeters as functions of time t in seconds by x = 20t + 3t² = 40 sin 2t, and z = 30 cos 2t. Determine the angle Teta1 between the acceleration a and the velocity v and the angle Teta2 between the position vector r and the acceleration a, both at time t = 3s.
- Determine the moments of inertia of the rectangular area about the x- and y-axes and find the polar moment of inertia about point O.Assume h0 = 0.37h, b0 = 0.15b.If you are given two vectors: A = 5i + 8j + 3k and B = 35i + 4j – 9k, what is the angle between the two vectors?explanation not neededA 50-m steel tape was used to measure a line and the initial pull = 5.5 kg. Pull at time of measurement = 8.0 kg. Weight of tape = 0.05 kg/m. E = 2.1 x 10^6 kg/cm^2? Cross section = 0.04 sq.cm. Measured distance between two points =488.650 m, in an inclined surface having a gradient of 3%. Find the correct horizontal distance between the two points. A. 486.456 C. 488.625 B. 490.844 D. 488.147 The distance from A to B taken at elevation 1200 m above sea level is 6,750 m. Determine the sea-level distance. A.6748.734 C. 6749.347 B. 6751.266 D.6750.274 ps. with solution, please.
- For Q#1, Y=157, X1=109.9, X2=157Given: A1= 3400, A2=800, A3=706.85834, A4=176.71458 Y1=42.5, Y2=26.666, Y3=52.7324, Y4= 62.5 X1=20, X2=53.333, X3=52.7324, X4=17.5 Total Area: 4730.14376 ȳ=40.604 x̄ (x-bar) = 30.6224 Please, I want you to solve the: 4.) Moment of Inertia About the x-axis Ix 5.) Moment of Inertia About the y – axis Iy 6.) Polar Moment of Inertia about the axes Jo 7.) Moment of Inertia About the centroidal x-axis Ix note: In locating the centroid of the entire section, Varignon's Theorem. Varignon's Theorem locates the centroid of a composite body. I hope you will use the formulas I will be giving.Find Q in m3/minute