5.00 mL of 7.00 x 10-3 M Fe(NO3)3 (7.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 9.00 mL of 5.00 x 10-3 M KSCN (5.00 times 10 to the minus 3rd power M KSCN) along with 6.00 mL of water. The concentration of [F e(SCN)2+] was found to be 2.00 x 10-4 M (2.00 times 10 to the minus 4th power M) at equilibrium.How many moles of [F e(SCN)2+] are present in the solution? Express your answer as a decimal number (no exponents).
5.00 mL of 7.00 x 10-3 M Fe(NO3)3 (7.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 9.00 mL of 5.00 x 10-3 M KSCN (5.00 times 10 to the minus 3rd power M KSCN) along with 6.00 mL of water. The concentration of [F e(SCN)2+] was found to be 2.00 x 10-4 M (2.00 times 10 to the minus 4th power M) at equilibrium.How many moles of [F e(SCN)2+] are present in the solution? Express your answer as a decimal number (no exponents).
Chapter17: Complexation And Precipitation Reactions And Titrations
Section: Chapter Questions
Problem 17.31QAP
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5.00 mL of 7.00 x 10-3 M Fe(NO3)3 (7.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 9.00 mL of 5.00 x 10-3 M KSCN (5.00 times 10 to the minus 3rd power M KSCN) along with 6.00 mL of water. The concentration of [F e(SCN)2+] was found to be 2.00 x 10-4 M (2.00 times 10 to the minus 4th power M) at equilibrium.How many moles of [F e(SCN)2+] are present in the solution? Express your answer as a decimal number (no exponents).
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