7.00 mL of 5.00 x 10-3 M Fe(NO3)3 (5.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 7.00 mL of 7.00 x 10-3 M KSCN (7.00 times 10 to the minus 3rd power M KSCN) along with 6.00 mL of water. The concentration of [F e(SCN)2+] was found to be 2.00 x 10-4 M (2.00 times 10 to the minus 4th power M) at equilibrium. How many moles of SCN- (SCN minus) are present in the solution at equilibrium? Express your answer as a decimal number (no exponents).

7.00 mL of 5.00 x 10-3 M Fe(NO3)3 (5.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 7.00 mL of 7.00 x 10-3 M KSCN (7.00 times 10 to the minus 3rd power M KSCN) along with 6.00 mL of water. The concentration of [F e(SCN)2+] was found to be 2.00 x 10-4 M (2.00 times 10 to the minus 4th power M) at equilibrium. How many moles of SCN- (SCN minus) are present in the solution at equilibrium? Express your answer as a decimal number (no exponents).

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter17: Complexation And Precipitation Reactions And Titrations

Section: Chapter Questions

Problem 17.31QAP

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8.00 mL of 9.00 x 10-3 M Fe(NO3)3 (9.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 5.00 mL of 5.00 x 10-3 M KSCN (5.00 times 10 to the minus 3rd power M KSCN) along with 6.00 mL of water. The concentration of [F e(SCN)2+] was found to be 1.00 x 10-4 M (1.00 times 10 to the minus 4th power M) at equilibrium. How many moles of SCN- (SCN minus) are present in the solution at equilibrium? Express your answer as a decimal number (no exponents).
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