5.25. Find (a) the area and (b) the moment of inertia about the y axis of the region in the xy plane bounded by y = 4 - x and the x axis. (a) Subdivide the region into rectangles as in Figure 5.1. A typical rectangle is shown in Figure 5.8. Then Required area = lim EfŠ,)Ax, k=1 = lim (4 - )Axę n kel = L (4 - x² )dx = 2 %3D 3 (b) Assuming unit density, the moment of inertia about the y axis of the typical rectangle shown in Figure 5.8 is f(5) Ax;. Then

Mathematics For Machine Technology
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Author:Peterson, John.
Publisher:Peterson, John.
Chapter65: Achievement Review—section Six
Section: Chapter Questions
Problem 44AR: Solve these prism and cylinder exercises. Where necessary, round the answers to 2 decimal places...
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5.25) my professor says I have to explain the steps in the solved problems in the picture. Not just copy eveything down from the text.

 

Applications (area, arc length, volume, moment of inertia)
5.25.
Find (a) the area and (b) the moment of inertia about the y axis of the region in the xy plane bounded by y =
4 – x and the x axis.
(a) Subdivide the region into rectangles as in Figure 5.1. A typical rectangle is shown in Figure 5.8. Then
n
Required area =
lim Ef5)Ax,
n 00
k=1
= lim (4 - )Ax,
n- 00
k=1
32
= L,(4 – x*)dx =
3
(b) Assuming unit density, the moment of inertia about the y axis of the typical rectangle shown in Figure 5.8
is f (5) Axy. Then
Ax-
2K
un
(-2, 0)
Šk
(2, 0)
Figure 5.8
Required moment of inertia = lim SGDAX, = lim š?(4 – )Ax,
n 00
k=1
n-00
k=1
128
= ,r*(4 – x²)dx =
15
- X
Transcribed Image Text:Applications (area, arc length, volume, moment of inertia) 5.25. Find (a) the area and (b) the moment of inertia about the y axis of the region in the xy plane bounded by y = 4 – x and the x axis. (a) Subdivide the region into rectangles as in Figure 5.1. A typical rectangle is shown in Figure 5.8. Then n Required area = lim Ef5)Ax, n 00 k=1 = lim (4 - )Ax, n- 00 k=1 32 = L,(4 – x*)dx = 3 (b) Assuming unit density, the moment of inertia about the y axis of the typical rectangle shown in Figure 5.8 is f (5) Axy. Then Ax- 2K un (-2, 0) Šk (2, 0) Figure 5.8 Required moment of inertia = lim SGDAX, = lim š?(4 – )Ax, n 00 k=1 n-00 k=1 128 = ,r*(4 – x²)dx = 15 - X
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