500.0 mL of 0.020 M Mn(NO3)2 are mixed with 1.0 L of 1.0 M Na2C204. The oxalate ion, C2042-, acts as a ligand to form complex ions with the Mn2+ ion. Mn2+ + C2042- MnC204 K1 = 7.9 x 103 [Mn(C204)2]2-2 MnC204 + C2042- K2 = 1.26 x 10-2 What is the equilibrium constant for the reaction below? Mn2+ + 2C2042-2 [Mn(C204)2]2-

Chemistry: An Atoms First Approach
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Author:Steven S. Zumdahl, Susan A. Zumdahl
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Chapter20: Transition Metals And Coordination Chemistry
Section: Chapter Questions
Problem 80AE
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500.0 mL of 0.020 M Mn(NO3)2 are mixed with
1.0 L of 1.0 M Na2C204. The oxalate ion,
C2042-, acts as a ligand to form complex ions
with the Mn2+ ion.
Mn2+ + C2042- MnC204
K1 = 7.9 x 103
[Mn(C204)2]2-2 MnC204 + C2042-
K2 =
1.26 x 10-2
What is the equilibrium constant for the
reaction below?
Mn2+ + 2C2042- [Mn(C204)2]2-
Transcribed Image Text:500.0 mL of 0.020 M Mn(NO3)2 are mixed with 1.0 L of 1.0 M Na2C204. The oxalate ion, C2042-, acts as a ligand to form complex ions with the Mn2+ ion. Mn2+ + C2042- MnC204 K1 = 7.9 x 103 [Mn(C204)2]2-2 MnC204 + C2042- K2 = 1.26 x 10-2 What is the equilibrium constant for the reaction below? Mn2+ + 2C2042- [Mn(C204)2]2-
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