52-2)180--2)180とろ (2x+プト3メナ2×+108けると=540 7x+197354 7x=343 X=49 12 108 とろとし 0 L4=82 LC=34タミ147 LD=249=98 3x 2X LE=108 213= 2x+7-105 17) m Z3 = (2x- 6)(x- 4) mZ5= 5(5x + 3)- (2x²-42) Determine the value of x so that line I will be parallel to line m. >m mL3+mL521800 8/レ 3/4 5/6 23 イメニ130-81 (2x-6)(x-5)+5(5x+3)-(2x?2)=/io 2A-8x-6x+24+25x+5-2x-42=D190 18) Given: XM bisects YXZ and ZYMZ. Prove: XM bisects ZYKZ statements reasons M. 19) Given: PS = RQ; PO = RS Prove: PQ|| SR statements reasons

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.2: Arithmetic Sequences
Problem 52E
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52-2)180--2)180とろ
(2x+プト3メナ2×+108けると=540
7x+197354
7x=343
X=49
12
108
とろとし
0 L4=82
LC=34タミ147
LD=249=98
3x 2X
LE=108
213= 2x+7-105
17) m Z3 = (2x- 6)(x- 4)
mZ5= 5(5x + 3)- (2x²-42)
Determine the value of x so that line I will be parallel to line m.
>m mL3+mL521800
8/レ
3/4
5/6
23
イメニ130-81
(2x-6)(x-5)+5(5x+3)-(2x?2)=/io
2A-8x-6x+24+25x+5-2x-42=D190
18) Given: XM bisects YXZ and ZYMZ. Prove: XM bisects ZYKZ
statements
reasons
M.
19) Given: PS = RQ; PO = RS Prove: PQ|| SR
statements
reasons
Transcribed Image Text:52-2)180--2)180とろ (2x+プト3メナ2×+108けると=540 7x+197354 7x=343 X=49 12 108 とろとし 0 L4=82 LC=34タミ147 LD=249=98 3x 2X LE=108 213= 2x+7-105 17) m Z3 = (2x- 6)(x- 4) mZ5= 5(5x + 3)- (2x²-42) Determine the value of x so that line I will be parallel to line m. >m mL3+mL521800 8/レ 3/4 5/6 23 イメニ130-81 (2x-6)(x-5)+5(5x+3)-(2x?2)=/io 2A-8x-6x+24+25x+5-2x-42=D190 18) Given: XM bisects YXZ and ZYMZ. Prove: XM bisects ZYKZ statements reasons M. 19) Given: PS = RQ; PO = RS Prove: PQ|| SR statements reasons
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