54. A heart defibrillator being used on a patient has an RC time constant of 10.0 ms due to the resistance of the patient and the capacitance of the defibrillator. (a) If the defibrillator has a capacitance of 8.00µF, what is the resistance of the path through the patient? (You may neglect the capacitance of the patient and the resistance of the defibrillator.) (b) If the initial voltage is 12.0 kV, how long does it take to decline to 6.00 × 102 V ?

Principles of Physics: A Calculus-Based Text
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ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter21: Current And Direct Current Circuits
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Answer a -b please

54. A heart defibrillator being used on a patient has an
RC time constant of 10.0 ms due to the resistance of the
patient and the capacitance of the defibrillator. (a) If the
defibrillator has a capacitance of 8.00µF, what is the
resistance of the path through the patient? (You may neglect
the capacitance of the patient and the resistance of the
defibrillator.) (b) If the initial voltage is 12.0 kV, how long
does it take to decline to 6.00 × 102 v ?
Transcribed Image Text:54. A heart defibrillator being used on a patient has an RC time constant of 10.0 ms due to the resistance of the patient and the capacitance of the defibrillator. (a) If the defibrillator has a capacitance of 8.00µF, what is the resistance of the path through the patient? (You may neglect the capacitance of the patient and the resistance of the defibrillator.) (b) If the initial voltage is 12.0 kV, how long does it take to decline to 6.00 × 102 v ?
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