5A. In shorthorn cattle, the polled condition is dominant over horned. Also, the heterozygous condition (RW) of red coat (R) and white coat (W) is roan, an example of codominance. (The roan coat contains both red and white fur because neither allele is dominant over the other). If a homozygous polled, white male is bred to a horned, red female, what will be the appearance of the F1 generation? a. Possible genotypes for Polled condition: Horned: b. Possible genotypes for Red coat:White Coat: Roan Coat: c. Male genotype Male possible gametes: Female genotypeFemale possible gametes: e. f. Genotypic Ratio: g. Phenotypic Ratio:
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Q: 5A. In shorthorn cattle, the polled condition is dominant over horned. Also, the heterozygous…
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- In cats, the genotype AA produces tabby fur color; Aa is also a tabby, and aa is black. Another gene at a different locus is epistatic to the gene for fur color. When present in its dominant W form (WW or Ww), this gene blocks the formation of fur color and all the offspring are white; ww individuals develop normal fur color. What fur colors, and in what proportions, would you expect from the cross AaWw Aa Ww?Consider a cross to investigate the pea pod texture trait, involving constricted or inflated pods. Mendel found that the traits behave according to a dominant/ recessive pattern in which inflated pods were dominant. If you performed this cross and obtained 650 inflated-pod plants in the F2 generation, approximately how many constricted-pod plants would you expect to have? 600 165 217 4681. In fruit flies, the phenotype for eye color is determined by a certain locus. E indicates the dominant allele and eindicates the recessive allele. The cross between a male wild-type fruit fly and a female white-eyed fruit flyproduced the following offspring.Wild-typeMaleWild-typeFemaleWhite-eyedMaleWhite-eyedFemaleBrown-eyedFemaleF1 0 45 55 0 1The wild-type and white-eyed individuals from the F1 generation were then crossed to produce the followingoffspring.F2 23 31 22 24 0(a) Determine the genotypes of the original parents (P generation) and explain your reasoning. You may usePunnett squares to enhance your description, but the results from the Punnett squares must be discussed inyour answer.(b) Use a Chi-squared test on the F2 generation data to analyze your prediction of the parental genotypes. Showall your work and explain the importance of your final answer.(c) The brown-eyed female in the F1 generation resulted from a mutational change. Explain what a mutation is,and discuss…
- 4.) A man and a woman have a child. The father is blood type A, and one of his parents was blood type A and the other was blood type O. The mother is blood type B, and one of her parents was blood type B, the other type O. Both the father and the mother are carriers of the Bombay allele. (Neither of the type-O grandparents were type O because of the Bombay allele – they had the regular type O genotype.) WhataretheoddsthattheirbabywillhavebloodtypeO? WhataretheoddsthattheirbabywillhavebloodtypeAB? (Hint – for this question, you should draw out a pedigree and fill in as much as you can for the genotypes of BOTH genes that are involved.)1) By convention, the recessive trait will determine the abbreviation used to track crosses if it is a mutant condition, since it stands out in contrast to the rest of the population. For example, if pea pods are typically green in color, a mutant condition might result in yellow pea pods; therefore, the lowercase letter ‘y’ would be used to depict the mutant state, yellow, while uppercase ‘Y’ would depict the wildtype (wt) condition, green. Remember that the mutant condition is not necessarily always recessive. 1 A) . If green is dominant wt (Y) and yellow is a recessive mutant condition (y), depict a Yy father mated with a YY mother in the Punnett. 1B) Considering the dominant allele, what colors are the parents in the cross above? Yy = _____________________ YY = _____________________ 1C) What colors are the offspring in the cross above? 1D) What is the phenotypic ratio of the offspring? 1E) What is the genotypic ratio of the offspring? (Remember, the genotypic ratio is based…7. The ability to roll your tongue (R) is dominant to lack of this ability (r). A. What is the genotype of a man who can roll his tongue if his father couldn’t? B. If a man who is heterozygous for tongue rolling marries a woman who is heterozygous, what would you predict for the genotypes and phenotypes of their children?
- 4. In dogs , curly hair is dominant to straight hair , and spotted coats are dominant to solid coats . If one dog has straight hair and is heterozygous for spotted coat is crossed with a dog that is heterozygous for both curly and spotted coat , determine the probability that the two dogs will have a puppy with curly hair and solid coat ?12. A heterozygous agouti mink is bred with a true-breeding white mink. Of the three offspring, one is an agouti male, one is a white male, and one is a black female. What is thesimplest explanation as to coat colour inheritance in these mink? the agouti allele is sex-linked a single gene is involved with the agouti allele being dominant a single gene is involved with the white allele being recessive at least two genes are involved1. A cow is heterozygous for three genes (WwPp) where W-White, w-Brown, P-Polled, p-Horned. Give the phenotypic and genotypic ratio of their offspring if the cow is inter se mated. 2.A male Sahiwal (RRHH) is crossed with a female Angus (Rrhh). Where R-Red, r-Brown, H-Horned, h-polled. Give the phenotypic and genotypic ratio of their offspring.
- 7) Skin color is a complex trait and while just a few genes account for the major difference between light and dark skin color, dozens of other genes participate. Assume in this hypothetical scenario there are only two genes for skin color, A and B. Each gene exhibits incomplete dominance. AABB (homozygous dominant for both genes) results in the darkest skin color and aabb (homozygous recessive for both genes) results in the lightest skin color. Tomas is heterozygous for both genes; his partner, Helga, is heterozygous for the A gene and homozygous recessive for the B gene. Construct a Punnett Square showing the cross of this couple. What are the expected genotypes and phenotypes of the children this couple could have?7. In rabbits, a locus involved in the control of coat colour may be occupied by any of fouralleles: Full colour (C), Sepia (ck), Cream (cd), or Albino (ca). A geneticist counted the numberof Full colour (C), Sepia (ck), Cream (cd) and Albino coat offspring resulting after crossesbetween Sepia (ck) and Cream (cd) coloured coated parents. The results were as follows.• Full colour (C): 152• Sepia (ck): 53• Cream (cd): 39• Albino (ca): 6Mendelian inheritance of this trait predicts that the ratio of Full colour (C) to Sepia (ck) to Cream(cd) to Albino (ca) should be 9:3:3:1. Do the experimental results support this mode ofinheritance?4) In frost moths, two alleles of one gene determine the character difference of spotted versus striped wings and two alleles of a separate, independent gene determine the character difference of orange wing background versus white wing background. The results for four matings of moth phenotypes are shown in the image attached. a) Assign the letter “s” to the wing pattern gene and letter “w” to the background color gene. Write in the capital letter for the dominant phenotype and the lower case letter for the recessive phenotype. Also, write whether each allele is dominant (D) or recessive (R). Wing pattern gene: Spotted - letter assignment:____ - dominant or recessive:____ Striped - letter assignment:____ - dominant or recessive:____ Background color gene: orange: - letter assignment:____ - dominant or recessive:____ white: - letter assignment:____ - dominant or recessive:_____ b) Based on the four matings in Question 4: What are the genotypes of each parent in each cross? If more…