6 Σ (-1)" n 1

Q: Dis cuss Ihe Conver gence of 9 Series 2. n= 1 3"

A: Consider the ratio test. ∑n=1nZ0n=z01-z0 By the ratio test the series converges when z0<1.…

Q: (п - 2)аn+1(2х — 3)п+1 + > ап-1 (2х — 3)"-1 n=0 n=2

A:

Q: Joltowing 1. +2y e" ounnha ans:

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Q: arctan(n) (iv) (-1)". n3 +n +1 n=1 [ Select ] n! 5n n=1

A: Solve the 4 and 5

Q: M8 M8 Με 4. Σ 15. Σ 6. Σ n=1 (n + 3)" 47² nt 1 – 5η4 (n + 3)" 4" η

A:

Q: 2 2 n(n-1)x", n²-n 37

A:

Q: P(Z -0.34) P(−0.25 <Z < -0.10)

A: (a)P(Z&lt; -1.12)=0.1313 From standard normal table,the graph is

Q: Inn n=1

A: Use Comparison test and P Test

Q: - n n 20 ₹u

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Q: 22n+1 2 (2n + 1)! n=1

A:

Q: 2 3 メキ3 %3D 3 SS412そ6

A: Given x232x+3634x+6 = 0

Q: 2) S(n)-10-2 at n 5

A: Given ,  f(n) = 10 (2)n     ......... (1) We have to find the value at n = 5 Put ,  n = 5 in…

Q: S =Ene 2 n=1

A: Use integral test to determine Whether the series os converges Or not

Q: p-

A:

Q: 20 (– 1)"2n n=0

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Q: P(0< z < ze)=0.4573

A:

Q: 6s – 5 4s +7 3s – 2 s +8s+ 25 ) s+7 s(s² – 3s – 10) naL 3²L² +n?n?

A:

Q: Evaluate [¹ ` = s+1 S s² (s+2)³

A:

Q: ompute 0 0 O0 3000 (3 3 3 3 3 3 3 3 3 0 0 0 0 0 0 0 0 0 F (3) B Otherwise (0) DI 13

A: To find the given matrix multiplication

Q: Ση 1 In 3" n=1

A: given,∑n=1∞ln13n = ∑n=1∞ln (3-n) =∑n=1∞ -n ln(3)   [since ln(ab) = b ln(a)]∴∑n=1∞ln13n = ∑n=1∞ -n…

Q: 6) P(-0.74 < Z < 1.74) 7) P(-1.74 < Z < 1.74) 8) P(Z < 1)

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Q: 3/n-1/2=n-5/n

A:

Q: 8 Evaluate E n(3 + 2n + n?) n = 1

A: Given : ∑n=18 n3+2n+n2 The objective is to find the sum of the above expression. Substitute the…

Q: 8 en Vn! n=0

A: We will check the convergence of the series.

Q: n+2 3. Evaluate E (-1)

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Q: P(-1.18<z≤ _________ )=0.6327   2. P ( ____ ≤z<0.85)=0.6363

A: we have to find probability for normal distribution.

Q: 10^n-3 first five  terms

A:

Q: 4m'n 23) -32 4m n 3mn 24) 4m 342 25) 3u0 26)

A: In algebra, to use numerals, symbols, and letters called variables, or pro-numerals, and…

Q: 4 3 1 + S2+4s+4 + s2+2s+2 53 1.

A:

Q: 8] n=1 1 5n2 + 5n

A: To Find: The sum ∑n=1∞15n2+5n

Q: 1 E(-1)". n(n+ 4) n=1

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Q: 9 Fess o65 5* +2 S 3.

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Q: : p(y-2|<10) p(z <2) =0.9772 y- N(2,25) 0.4594 0.5944 O 0.9544

A: It is known that, Z score= (y-mean)/standard deviation. Given that, Mean= 2 and variance= 25  So…

Q: 2 -n S, = En -Σ пе n=1

A: For the solution follow the next step.

Q: 00 E(-1)"n" 2(-1)"n¬1/10| n=1

A: The given series is ∑n=1∞-1nn-1110. Alternative series test: A series ∑n=1∞-1nan convergent if…

Q: 2(-1)n-1_6" n=1 5n+1

A: To find: ∑n=1∞-1n-16n5n+1

Q: In n n + 1 а) аn b) an = n n 1+ (-1)" c) An 1 d)an n II

A: Note:  Since we can solve at most three subparts in a question, we have solved the first three…

Q: 8. Q# 1 n! 5" n=1

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Q: 27. E (4 - n) n=2

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Q: 5 Σ (3n + 2)(2n – 1) n = 3

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Q: 5. Between z=-1.98 and z = -0.03

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Q: 2. ÏI (1+n-13). n=1 00

A: Please check step 2 for the solution.

Q: series: n(2n + 5) 8" (n + 1) In(2n + 3)

A:

Q: p(-1.80<z<0.20)

A: We have to find P(-1.80&lt;z&lt;0.20)  z is standard normal variable with mean 0 and standard…

Q: 3. II (1 – 3-"). n=1 In(1+æ)

A: Please check step 2 for the solution.

Q: Evaluate L-tcos 5t. 10s А. (s +25 )* s2 - 25 - (s² +25)* 25s C. - (s° +5)* s2 -5 D. (s* +5) 50s E.…

A:

Q: P(-0.63<Z<1.85)=

A: Given : z₁=-0.63 z₂=1.85

Q: 0.12093 He(s) = %3D (s2 +0.3640s +0.4945)(s2 +0.9945s + 0.4945)(s2 + 1.3585s + 0.4945)

A: We need to find the Partial fraction expansion in the image below. So,…

Q: 3 n2 + 9n + 18 n=1

A:

Q: M(-1)"+1cos²n n = 1

A: