6. How many milliliters of 0.175 M Hg(NO3)2 is needed to completely precipitate 2.50 g KI? (Molar mass of KI = 166.0 g/mol) %3D Hg(NO3)2(aq) + 2 KI(aq) 2 KNO3(aq) + Hgl2(s)

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter3: Chemical Reactions
Section: Chapter Questions
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6. How many milliliters of 0.175 M Hg(NO3)2
is needed to completely precipitate 2.50 g
KI?
(Molar mass of KI = 166.0 g/mol)
%3D
Hg(NO3)2(aq) + 2 KI(aq)
2 KNO3(aq) + Hgl2(s)
Transcribed Image Text:6. How many milliliters of 0.175 M Hg(NO3)2 is needed to completely precipitate 2.50 g KI? (Molar mass of KI = 166.0 g/mol) %3D Hg(NO3)2(aq) + 2 KI(aq) 2 KNO3(aq) + Hgl2(s)
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