*6. In a redox titration, 12.52 mL of a 0.3264 M KMNO4 solution were required to titrate 1.7832 g of a reducing agent (“X"). If the reducing agent undergoes a 3-electron change per formula unit: a. Write the two ionic half reactions and the balanced net ionic equation. t 3e > 5 Mn04 caq) Ionic MnO4: Ionic Reducing Agent: X X+3c- Net ionic: b. Calculate the molar mass of the reducing agent.

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Chapter18: Oxidation–reduction Reactions And Electrochemistry
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I need help with number 6, a and b.
*6. In a redox titration, 12.52 mL of a 0.3264 M KMNO4 solution were required to titrate
1.7832 g of a reducing agent (“X"). If the reducing agent undergoes a 3-electron change
per formula unit:
a. Write the two ionic half reactions and the balanced net ionic equation.
Ionic MnOg¯: /Mn O4raqt 3e-> S MnO4 ca
Ionic Reducing Agent: X X + 3c-
Net ionic:
b. Calculate the molar mass of the reducing agent.
94
Transcribed Image Text:*6. In a redox titration, 12.52 mL of a 0.3264 M KMNO4 solution were required to titrate 1.7832 g of a reducing agent (“X"). If the reducing agent undergoes a 3-electron change per formula unit: a. Write the two ionic half reactions and the balanced net ionic equation. Ionic MnOg¯: /Mn O4raqt 3e-> S MnO4 ca Ionic Reducing Agent: X X + 3c- Net ionic: b. Calculate the molar mass of the reducing agent. 94
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