60.0 0.500 mm (a) Red blood cells often become charged and can be treated as point charges. Healthy red blood cells are negatively charged, but unhealthy cells (due to the presence of a bacteria, for example) can become positively charged. In the figure, three red blood cells are oriented such that they are located on the corners of an equilateral triangle. The red blood cell charges are A 1.90 pC, B = 6.50 pc, and C= -4.80 pC. Given these charges, what would the magnitude and direction of the electric field be at cell A? (1 pc- 1 x 10-12 C.) magnitude ✓N/C 210191.91 77.605 x direction What are the components of the net electric field? Can you then use these to find the direction? counterclockwise from the +x-axis

College Physics
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Chapter15: Electric Forces And Electric Fields
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Problem 43P: A Van de Graaff generator is charged so that a proton at its surface accelerates radially outward at...
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60.0
0.500 mm
(a) Red blood cells often become charged and can be treated as point charges. Healthy red blood cells are negatively charged, but unhealthy cells (due to the presence of a bacteria, for example) can
become positively charged. In the figure, three red blood cells are oriented such that they are located on the corners of an equilateral triangle. The red blood cell charges are A = 1.90 pC, B = 6.50 PC,
and C= -4.80 pC. Given these charges, what would the magnitude and direction of the electric field be at cell A? (1 pC= 1 x 10-12 C.)
magnitude
210191.91
✓N/C
X
77.605
direction
What are the components of the net electric field? Can you then use these to find the direction?" counterclockwise from the +x-axis
Transcribed Image Text:60.0 0.500 mm (a) Red blood cells often become charged and can be treated as point charges. Healthy red blood cells are negatively charged, but unhealthy cells (due to the presence of a bacteria, for example) can become positively charged. In the figure, three red blood cells are oriented such that they are located on the corners of an equilateral triangle. The red blood cell charges are A = 1.90 pC, B = 6.50 PC, and C= -4.80 pC. Given these charges, what would the magnitude and direction of the electric field be at cell A? (1 pC= 1 x 10-12 C.) magnitude 210191.91 ✓N/C X 77.605 direction What are the components of the net electric field? Can you then use these to find the direction?" counterclockwise from the +x-axis
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