29.8fill in blanks please In the figure below, the current in the long, straight wire is I₁ = 4.70 A and the wire lies in the plane of the rectangular loop, which carries acurrent I₂ = 10.0 A. The dimensions in the figure are c = 0.100 m, a = 0.150 m, and l = 0.425 m. Find the magnitude and direction of thenet force exerted on the loop by the magnetic field created by the wire.41₂←ca For the total magnetic force for sides 1 and 3 of the loop, we have the following.MOI₁I₂lF= F₁+F₂= H²0²1¹2¹²-2π1c + a1¹)₁ =C4 x 10-7N/A²) (0= The correct answer is not zero. A²A²)(2π-a2π (c(c + a)0.425Xm-(0The correct answer is not zero. mXThe correct answer is not zero. m²m²)0

I1 = 4.70 A. ; I2 = 10.0 A, l=0.425 m, c=0.100 m, a = 0.150 m

For the total magnetic force for sides 1 and 3 of the loop, we have the following. → -a F = F₁ + F₂ = Hoſ¹¹2² ( _ 1_ − 1); - #0²1/2² ( 72 ) = 2 2π c + a 2π c(c + a) (4π × 10-7 N/A²)(0 = The correct answer is not zero. A A²)( 2π 0.425 X m -(⁰ The correct answer is not zero. m X X The correct answer is not zero. m²)

For the total magnetic force for sides 1 and 3 of the loop, we have the following. → -a F = F₁ + F₂ = Hoſ¹¹2² ( _ 1_ − 1); - #0²1/2² ( 72 ) = 2 2π c + a 2π c(c + a) (4π × 10-7 N/A²)(0 = The correct answer is not zero. A A²)( 2π 0.425 X m -(⁰ The correct answer is not zero. m X X The correct answer is not zero. m²)

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter22: Magnetic Forces And Magnetic Fields

Section: Chapter Questions

Problem 43P: In Figure P22.43, the current in the long, straight wire is I1 = 5.00 A and the wire lies in the...

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