question 67 only follows:C(q) =10,000,000+500q+0.04q² &R(q) = 2,500q – 0.01q²%3Da. Using the marginal approach, determine the profit-maximizing level of output q'.b. What is the maximum profit?Optimum & Inflection Points (62-67) - Draw the graphs of the following functions and/orrelations and identify the locations of the optimum and the inflection points using the 1st and the2nd derivatives.62) y = f(x)= / 4x – 10 = (4x–10)½sRelation only-363) y = f(x)=1- xRelation and Function, both64) y = f(x)=(2x-7)*Relation and Function, both65) y = f(x)= /10-4x = (10-–4x)½Relation onlyx²66) y = f(x)=1- x2Relation and Function, both67) y = f(x)=(2x-7)°3.Relation and Function, both68) Cost Minimization - The cost function of purchasing, owning and maintaining inventoryannually for a firm's product is C = f(q)=(4,860/q)+15q +75,000 where C denotes annualinventory cost in dollars, and q equals the number of units of products ordered each time thefirm replenishes the inventory.%3D%Da. Determine the ordo

Name: question 67 only follows:C(q) =10,000,000+500q+0.04q² &R(q) = 2,500q –
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Description: question 67 only follows:C(q) =10,000,000+500q+0.04q² &R(q) = 2,500q – 0.01q²%3Da. Using the marginal approach, determine the profit-maximizing level of output q'.b. What is the maximum profit?Optimum & Inflection Points (62-67) - Draw the graphs of

Step:-1 Given that y=f(x)=2x-73 Graph of the function is Using graph, we can see this relation has…

Answered: 67) y = f(x)=(2x–7)

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

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question 67 only

follows:
C(q) =10,000,000+500q+0.04q² &
R(q) = 2,500q – 0.01q²
%3D
a. Using the marginal approach, determine the profit-maximizing level of output q'.
b. What is the maximum profit?
Optimum & Inflection Points (62-67) - Draw the graphs of the following functions and/or
relations and identify the locations of the optimum and the inflection points using the 1st and the
2nd derivatives.
62) y = f(x)= / 4x – 10 = (4x–10)½s
Relation only
-
3
63) y = f(x)=
1- x
Relation and Function, both
64) y = f(x)=(2x-7)*
Relation and Function, both
65) y = f(x)= /10-4x = (10-–4x)½
Relation only
x²
66) y = f(x)=
1- x
2
Relation and Function, both
67) y = f(x)=(2x-7)°
3.
Relation and Function, both
68) Cost Minimization - The cost function of purchasing, owning and maintaining inventory
annually for a firm's product is C = f(q)=(4,860/q)+15q +75,000 where C denotes annual
inventory cost in dollars, and q equals the number of units of products ordered each time the
firm replenishes the inventory.
%3D
%D
a. Determine the ordo

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