6a. Blood Type: Multiple Alleles One of the offspring with blood type B from the cross above (in 5a) is crossed with a person with blood type AB. Please fill in the Punnett square and the genotypic and phenotypic ratios for this cross below. (blank) AB BB Al BI 6b. Write the proportions, percents, and ratios for the genotypes and phenotypes of this cross Genotype: Proportions/Percents: Ai = | /4 or Bi = /4 or AB = /4 or AA = /4 or BB = /4 or Ratio: Phenotype: Proportions/Percents: Blood type A = 14 or Blood type B= /4 or Blood type AB = 14 or Ratio:
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- A man of blood group A is being sued by a woman of blood group B for paternity. The women’s child is blood group O. A) Is this man the father of this child? Explain. B) If this man actually is the father of this child, specify the genotypes of both parents. C.) If it was impossible for this group A man to be the father of a type O child, regardless of the mother’s genotype, specify his genotype. D.) If a man was blood group AB, could he be the father of a group O child? Why/why not?1. A mother with blood type A has a child with blood type O, and she claims that Mister X is the father. Mister X denies that he could possibly be the father, because he has blood type B. If you were the judge presiding over this case, which of the following arguments would you find most convincing? a. Mr. X could be the father if his blood genotype is IBIB, and the mother’s blood genotype is IAIA b. Mr. X cannot be the father because a child with blood type O cannot have a parent with blood type B c. Mr. X could be the father if his blood genotype is IBi, and the mother’s blood genotype is IAi d. Mr. X cannot be the father because a parent with blood type B cannot have a child with blood type O e. Mr. X cannot be the father because the human ABO blood types are sex-linked traits 2. A monohybrid cross between two pea plants producing yellow peas, resulting in an F1 phenotypic ratio of 3:1 (three yellow pea plants to one green pea plant) indicates what about the parental pea plants?…Cross a homozygous tall female carrier for hemophilia with a short normal male. Give genotypic and phenotypic ratios of the offspring. Use T = Tall, and t = short for one trait, and H =normal, and h = hemophilia for the second sex-linked trait. The Cross is: XHXhTT X XYtt . Question: What is the phenotypic ratio? a. 1:2:4:4 b. 4:4:4:4 c. 3:2:1:4 d. None is correct
- 1. Construct a pedigree chart of the trait traced in the situation below.2. The pedigree chart must be constructed with the names and genotypes at the bottom of every individual in the chart.If it is autosomal: Always use the first letter of the dominant trait to represent the dominant allele. For example, if the dominant trait is red, so the allele R-red, while r-yellow. For example, if the person is homozygous dominant for curly hair, we write CC as his genotype. If sex-linked, do not forget to write the parents’ chromosomes (XX-female, XY-male), with their corresponding superscripts (dominant or recessive). The superscript must be based on the first letter of the disorder. For example, the mother is a carrier of hemophilia (which is x-linked recessive), so we write XHXh. If the father has hemophilia, we write XhY. Put the pedigree chart using code properly. The situation is given below: Trait: NeurofibromatosisThe dominant form is neurofibromatosis, caused by the production of…1. Construct a pedigree chart of the trait traced in the situation below.2. The pedigree chart must be constructed with the names and genotypes at the bottom of every individual in the chart.If it is autosomal: Always use the first letter of the dominant trait to represent the dominant allele. For example, if the dominant trait is red, so the allele R-red, while r-yellow. For example, if the person is homozygous dominant for curly hair, we write CC as his genotype. If sex-linked, do not forget to write the parents’ chromosomes (XX-female, XY-male), with their corresponding superscripts (dominant or recessive). The superscript must be based on the first letter of the disorder. For example, the mother is a carrier of hemophilia (which is x-linked recessive), so we write XHXh. If the father has hemophilia, we write XhY. Put the pedigree chart using code properly. The situation is given below: Trait: NeurofibromatosisThe dominant form is neurofibromatosis, caused by the production of…7. Mr. and Mrs. Weasley have 7 children and all of the children have red hair like their parents. Mrs. Weasley has brown eyes but Mr. Weasley's eye color is unknown. Four of their 7 children have blue eyes and three have brown eyes. a. I Mr. Weasley's eye color is blue, what must be Mrs. Weasley's genotype? Explain how you arrive at your answer. Draw a Punnett square to support your answer. Explanation
- 1. A man with AB blood type marries a woman with AB blood type. What are the expected genotypic and phenotypic ratios for the children? a) What is the genotypic ratio of the above cross (Write number next to genotype)? ___________________________________________________________________ b) What is the phenotypic ratio of the above cross? (Write number next to phenotype)? ___________________________________________________________________1. A man with O blood type marries a woman with AB blood type. What are the expected genotypic and phenotypic ratios for the children? a) What is the genotypic ratio of the above cross (Write number next to genotype)? ___________________________________________________________________ b) What is the phenotypic ratio of the above cross? (Write number next to phenotype)? ___________________________________________________________________Classical hemophilia is a sex-linked disease caused by a recessive gene on the X chromosome. (Hemophilia refers to diseases that cause delays in blood clotting.) If a woman who is acarrierof classical hemophilia has children with a normal male, give the ratios of the possible offspring with respect to classical hemophilia. Be sure to state both the genotypes and the phenotypes of each offspring. For genotypes, use X for a normal X chromosome, Xh for an X chromosome with the hemophilia gene, and Y for a normal Y chromosome. For phenotypes, if the offspring is female, be sure to state if homozygous normal, a carrier, or has the disease. If the offspring is a male, be sure to state if normal or has the disease.
- Could someone please help me with this grade 11 bio dihybrid cross problem in detail and how to solve this question, using a strategy? Assume that curly hair (C) is dominant to straight hair. Albinism (P ) is recessive to normal skin pigmentation. A woman who is heterozygous for curly hair and albinism has a child. The father is homozygous dominant for curly hair and has albinism. (a) Determine the possible phenotypes for their child. (double-crossing, Puneet square)(b) Calculate the four different probabilities of a child beingboth a male and of each phenotype.(c) What is the probability that the child will expressalbinism and have curly hair like his father?Blood type is determined by multiple codominant alleles of the I gene, IA, IB, and i, where ii results in type O. The genotypes of a husband and wife are IAIB x IAi. Among the blood types of their children, how many different genotypes and phenotypes are possible? Group of answer choices 2 genotypes, 3 phenotypes 4 genotypes, 3 phenotypes 3 genotypes, 3 phenotypes 3 genotypes, 4 phenotypes16.A couple is suspecting that their baby was switched at the hospital. The mother has blood type A, the father has blood type B, and the baby has blood type O. Which among the following conditions would prove that the baby is switched? A. Mother’s genotype: IAIA & Father’s genotype: ii B. Mother’s genotype: ii & Father’s genotype: IBIB C. Mother’s genotype: IAIA & Father’s genotype: IBIB D. Mother’s genotype: IAi & Father’s genotype: IBi