Help me please fill out the questions NameModDatePRACTICE-PUNNETT SQUARESSeed ShapePod ShapePod ColorDominantRecessiveDominantRecessiveDominantRecessiveRoundWrinkleFullFlatGreenYellowRfGDirections: Complete the following crosses using a Punnett Square. For each one give what the genes say(genotypes) and what the cross would look like (phenotypes).1.Show a cross between FF x Ff.2.Show a cross between Gg x Gg

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Name Mod Date PRACTICE-PUNNETT SQUARES Seed Shape Pod Shape Pod Color Dominant Recessive Dominant Recessive Dominant Recessive Round Wrinkle Full Flat Green Yellow R f G g Directions: Complete the following crosses using a Punnett Square. For each one give what the genes say (genotypes) and what the cross would look like (phenotypes). 1. Show a cross between FF x Ff. 2. Show a cross between Gg x Gg

Name Mod Date PRACTICE-PUNNETT SQUARES Seed Shape Pod Shape Pod Color Dominant Recessive Dominant Recessive Dominant Recessive Round Wrinkle Full Flat Green Yellow R f G g Directions: Complete the following crosses using a Punnett Square. For each one give what the genes say (genotypes) and what the cross would look like (phenotypes). 1. Show a cross between FF x Ff. 2. Show a cross between Gg x Gg

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter4: Pedigree Analysis In Human Genetics

Section: Chapter Questions

Problem 19QP: Analysis of X-Linked Dominant and Recessive Traits Suppose a couple, both phenotypically normal,...

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My Question is what is the probability their first child will have hemophilia and drawn pedigrees for family members with genotypes. My explantion so far: A man has both X and Y chromosomes as sex chromosomes in his body. Here, though the brother of the man is hemophiliac, a man can’t be a carrier of hemophilia. So, it can be said that his chromosome is “XnY”.Here, the “n” stands for “normal”.Though the paternal uncle is hemophiliac, a man cannot be a carrier of hemophilia, his niece will not be a career. So it can be said that the woman is also not a carrier and has the “XnX” chromosome.So, as the mother is not a carrier, their first child does not have a chance of having hemophilia. This can be determined as it is known that there is no hidden carrier of hemophilia in the family.
Can you show me how to do it? Show me the cross and explanation please. Testing for independent assortment
Maria (AA-) and Jason (AB+) Phillips had twins, a boy and a girl. Lily (AO-) and Charles (AO-) Smith had a boy. When Maria received her son’s birth certificate, his blood type was labeled O-. Based on the information provided, what is the best possible explanation for the O- blood type on the birth certificate Maria received? What is the best explanation for the Smith’s son whose blood was labeled AB-?
The accompanying pedigree is for a rare, but relativelymild, hereditary disorder of the skin.a. How is the disorder inherited? State reasons for youranswer.b. Give genotypes for as many individuals in thepedigree as possible. (Invent your own defined allelesymbols.)c. Consider the four unaffected children of parentsIII-4 and III-5. In all four-child progenies from parentsof these genotypes, what proportion is expected tocontain all unaffected children?(picture added)
Monohybrid crosses Using Punnet square
RrxRR Genotyperatioofoffspring___________________ Phenotyperatioofoffspring__________________
Shown above is a family pedigree tree in which family members afflictedwith the disease Haemophilia are shown with filled-in squares (male) or circles (females). A couple is trying to determine the likelihood of passingon the disease to their future children (represented by the ? symbolabove) because the hemophilia runs in the woman’s family. Turner syndrome is a disease in which an individual is bornwith only a single X chromosome. Suppose the woman in thecouple is a carrier for hemophilia and has a child with Turnersyndrome. Would this child have the disease?
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Eva’s parents, John and Cher. Are both type AB. John questioned Cher’s fidelity when Eva turned out to be a type O. Assuming that Cher is indeed loyal to her husband, why did Eva turn out to be type O? Help Cher prove her innocence by showing the possible genotypes of John and Cher. Show also the COMPLETE cross that produced Eva.
Using the Dihybrid Cross, Give the Total Number and Types of Gametes formed of MmNnOoPPQQRrssTtQq. Show all the gametes that are formed by the following genotypes.
Codominance: draw a Punnett Square for a AA mom with a AB dad. i. If you have type AB blood type, what possible blood types could your parents have? ii. If you have type A blood, can either of your parents have type O? iii. If you have type O blood, could either of your parents be type AB? Upload your image using the paperclip icon
Neurospora of genotype a + c are crossed withNeurospora of genotype + b +. (Here, + is shorthandfor the wild-type allele.) The following tetrads areobtained (note that the genotype of the four sporepairs in an ascus are listed, rather than listing alleight spores):a + c a b c + + c + b c a b + a + ca + c a b c a + c a b c a b + a b c+ b + + + + + b + + + + + + c + + ++ b + + + + a b + a + + + + c + b +137 141 26 25 2 3a. In how many cells has meiosis occurred to yieldthese data?b. Give the best genetic map to explain these results.Indicate all relevant genetic distances, both betweengenes and between each gene and the centromere.c. Diagram a meiosis that could give rise to oneof the three tetrads in the class at the far right inthe list