4a. Codominance One of the speckled offspring from the first cross is crossed with another speckled chicken. Please fill in the Punnett square and the genotypic and phenotypic ratios below for this cross. (blank) 4b. Write the proportions, percents, and ratios for the genotypes and phenotypes of this cross Genotype: Proportions/Percents: BB = /4 or BW = /4 or WW = /4 or Ratio: Phenotype: Proportions/Percents: Black chickens = /4 or Speckled chickens = 14 or White chickens = 14 or Ratio:
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- 1. A man with AB blood type marries a woman with AB blood type. What are the expected genotypic and phenotypic ratios for the children? a) What is the genotypic ratio of the above cross (Write number next to genotype)? ___________________________________________________________________ b) What is the phenotypic ratio of the above cross? (Write number next to phenotype)? ___________________________________________________________________Could someone please help me with this grade 11 bio dihybrid cross problem in detail and how to solve this question, using a strategy? Assume that curly hair (C) is dominant to straight hair. Albinism (P ) is recessive to normal skin pigmentation. A woman who is heterozygous for curly hair and albinism has a child. The father is homozygous dominant for curly hair and has albinism. (a) Determine the possible phenotypes for their child. (double-crossing, Puneet square)(b) Calculate the four different probabilities of a child beingboth a male and of each phenotype.(c) What is the probability that the child will expressalbinism and have curly hair like his father?Ch. 13-3 Refer to problem 2. Determine the predicted genotype frequencies among the offspring of the following crosses:a. AABB × aaBB b. AaBB × AABb c. AaBb × aabb d. AaBb × AaBb
- 1. A woman who is heterozygous for the brown eye and blue eye alleles marries a man with blue eyes. What are the genotypes and phenotypes of the children? a) What is the genotypic ratio of the above cross (Write number next to genotype)? ___________________________________________________________________ b) What is the phenotypic ratio of the above cross? (Write number next to phenotype)? ___________________________________________________________________1) By convention, the recessive trait will determine the abbreviation used to track crosses if it is a mutant condition, since it stands out in contrast to the rest of the population. For example, if pea pods are typically green in color, a mutant condition might result in yellow pea pods; therefore, the lowercase letter ‘y’ would be used to depict the mutant state, yellow, while uppercase ‘Y’ would depict the wildtype (wt) condition, green. Remember that the mutant condition is not necessarily always recessive. 1 A) . If green is dominant wt (Y) and yellow is a recessive mutant condition (y), depict a Yy father mated with a YY mother in the Punnett. 1B) Considering the dominant allele, what colors are the parents in the cross above? Yy = _____________________ YY = _____________________ 1C) What colors are the offspring in the cross above? 1D) What is the phenotypic ratio of the offspring? 1E) What is the genotypic ratio of the offspring? (Remember, the genotypic ratio is based…1.What is the genotype of the F1 generation of the corn monohybrid cross described above? 2.What is the phenotype of the F1 generation of the corn monohybrid cross described above? 3.What are the possible maternal and paternal genotypes of the F1 gametes of the corn monohybrid cross described above?
- 1. A mother with blood type A has a child with blood type O, and she claims that Mister X is the father. Mister X denies that he could possibly be the father, because he has blood type B. If you were the judge presiding over this case, which of the following arguments would you find most convincing? a. Mr. X could be the father if his blood genotype is IBIB, and the mother’s blood genotype is IAIA b. Mr. X cannot be the father because a child with blood type O cannot have a parent with blood type B c. Mr. X could be the father if his blood genotype is IBi, and the mother’s blood genotype is IAi d. Mr. X cannot be the father because a parent with blood type B cannot have a child with blood type O e. Mr. X cannot be the father because the human ABO blood types are sex-linked traits 2. A monohybrid cross between two pea plants producing yellow peas, resulting in an F1 phenotypic ratio of 3:1 (three yellow pea plants to one green pea plant) indicates what about the parental pea plants?…1. Construct a pedigree chart of the trait traced in the situation below.2. The pedigree chart must be constructed with the names and genotypes at the bottom of every individual in the chart.If it is autosomal: Always use the first letter of the dominant trait to represent the dominant allele. For example, if the dominant trait is red, so the allele R-red, while r-yellow. For example, if the person is homozygous dominant for curly hair, we write CC as his genotype. If sex-linked, do not forget to write the parents’ chromosomes (XX-female, XY-male), with their corresponding superscripts (dominant or recessive). The superscript must be based on the first letter of the disorder. For example, the mother is a carrier of hemophilia (which is x-linked recessive), so we write XHXh. If the father has hemophilia, we write XhY. Put the pedigree chart using code properly. The situation is given below: Trait: NeurofibromatosisThe dominant form is neurofibromatosis, caused by the production of…1. Construct a pedigree chart of the trait traced in the situation below.2. The pedigree chart must be constructed with the names and genotypes at the bottom of every individual in the chart.If it is autosomal: Always use the first letter of the dominant trait to represent the dominant allele. For example, if the dominant trait is red, so the allele R-red, while r-yellow. For example, if the person is homozygous dominant for curly hair, we write CC as his genotype. If sex-linked, do not forget to write the parents’ chromosomes (XX-female, XY-male), with their corresponding superscripts (dominant or recessive). The superscript must be based on the first letter of the disorder. For example, the mother is a carrier of hemophilia (which is x-linked recessive), so we write XHXh. If the father has hemophilia, we write XhY. Put the pedigree chart using code properly. The situation is given below: Trait: NeurofibromatosisThe dominant form is neurofibromatosis, caused by the production of…
- Could someone please help me with this grade 11 bio dihybrid cross problem on how to solve this question, using a strategy in detail! Assume that curly hair (C) is dominant to straight hair. Albinism (P ) is recessive to normal skin pigmentation. A woman who is heterozygous for curly hair and albinism has a child. The father is homozygous dominant for curly hair and has albinism. (a) Determine the possible phenotypes for their child. (double-crossing, Punnet square) (how to display the traits) (b) Calculate the four different probabilities of a child beingboth a male and of each phenotype. (steps in solving this) (c) What is the probability that the child will expressalbinism and have curly hair like his father? (steps in solving this)A true-breeding rabbit with agouti (mottled, grayish brown) fur crossed with a true-breeding rabbit with chinchilla (silver) fur produces all agouti offspring. A true-breeding chinchilla rabbit crossed with a true-breeding Himalayan rabbit (white fur with pigmented nose, ears, tail, and legs) produces all chinchilla offspring. A true-breeding Himalayan rabbit crossed with a true-breeding albino rabbit produces all Himalayan offspring. Explain the inheritance of the fur colors.In Section 12.3, ''Laws of Inheritance," an example of epistasis was given for the summer squash. Cross white WAvYy heterozygotes to prove the phenotypic ratio of 12 white:3 yellow:l green that was given in the text.