Question
Asked Nov 9, 2019

(6x+1)y^2y'+3x^2+2y^3=0

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Expert Answer

Step 1

Check whether the given differential equ...

+(3x2 2y30
dx
The given differential equation is (6x +1)p2 dy
Seperate the variables as follows
(6x+1)y'dy +(3x2 +2y)d = 0
Compare with Mdx + Ndy 0. Here N
(6x +1) y and M (3x2 +2y
дм
6y2 and
y
- 6y2
ax
ом
Ох
The differential equation is exact
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+(3x2 2y30 dx The given differential equation is (6x +1)p2 dy Seperate the variables as follows (6x+1)y'dy +(3x2 +2y)d = 0 Compare with Mdx + Ndy 0. Here N (6x +1) y and M (3x2 +2y дм 6y2 and y - 6y2 ax ом Ох The differential equation is exact

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Math

Calculus

Differential Equations

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