*7-32.d The double T-beam is fabricated by welding the three plates together as shown. Determine the shear stress in the weld necessary to support a shear force of V 80 kN.
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- f. Calculate the maximum safe load "P" in KN Two A36 16mm Thick Steel Plates Are Connected By Four Rivets With Fv=152 MPa As Shown. Given: Rivet Dia 20 mm x=100 mmDetermine the capacity of the details shown below. A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksi g) what is the flexural/local buckling capacity of the shear plate of the shear connection in kips? (2 decimal places)Prob 01: An 18” depth beam is bolted to a 24” depth girder is connected similar to that in figure shown below. Thediameter of the rivet is 20mm and the angles are each 100mm x 100mm x 12mm thick. For each bolt, assume thatthe allowable bearing stress is 220 MPa. Determine the allowable load P in KN on the connection. *show all theload P in kN for bearing stressBeam web thickness = 5mmGirder web thickness =
- The riveted lap connection shown consists of two(2) – PL 12 mm × 280 mm. 1. If allowable bearing stress in holes is 1.2Fu where Fu is the ultimate strength of the plate and which is equal to 400 MPa, find the maximum allowable force P that can be applied neglecting effect of eccentricity. a. 563.3 kN b. 460.8 kN c. 683. 6 kN d. 405.9 kN 2. If allowable yielding of gross area is Fy/1.67, where Fy is the yield strength of the plate and which is equal to 250 MPa, find the maximum allowable force P that can be applied neglecting effect of eccentricity. a. 534 kN b. 560 kN c. 446 kN d. 503 kN 3. If diameter of hole equals diameter of rivet, what is the net area of edge-3-4-edge in square millimeters? a. 2540 b. 2590 c. 2880 d. 20408) what is the flexural rupture capacity of the shear plate of the shear connection in kips? (2 decimal places) A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksiUse LRFD and design the tension members of the roof truss shown in Figure below. Use double-angle shapes throughout and assume 10-mm-thick gusset plates and welded connections. Assume a shear lag factor of U = 0.80. The trusses are spaced at 9 meters. Use A36 steel and design for te following loads. Metal deck : 190 Pa of roof surface Built-up roof : 575 Pa of roof surface Purlins : 145 Pa of roof surface (estimated) Roof Live Load : 960 Pa of horizontal projection Truss weight : 240 Pa of horizontal projection (estimated)
- e. Calculate "P" in KN considering failure on bearing on block shear Two A36 16mm Thick Steel Plates Are Connected By Four Rivets With Fv=152 MPa As Shown. Given: Rivet Dia 20 mm x=100 mmA flange bolt coupling has ten steel 25.4 mm diameter bolts evenly tighten around a 415 mm bolt circle. Determine the torque capacity of the connection if the allowable shearing stress in the bolt is 50 MN/m2 . A. 59.95 kN - m B. 52.6 kN - m C. 46.15 kN - m D. 43.8 kN – m20) what is the weld capacity perpedicular to the beam of the flange connection in kips? (2 decimal places) A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksi
- g) what is the flexural/local buckling capacity of the shear plate of the shear connection in kips? (2 decimal places)A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksiDetermine the capacity of the details shown below.A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksi d) what is the shear yielding capacity of the shear plate of the shear connection in kips? (2 decimal places)The cutaway view shows a solid aluminum alloy [L2 = 800 mm; A2 = 667 mm2; E2 = 70 GPa] rod (2) within a closed-end bronze [L1 = 818 mm; A1 = 1211 mm2; E1 = 100 GPa] tube (1). Before the load P is applied, there is a clearance of 3 mm between the rod flange at B and the tube closure at A. After load P = 220 kN is applied, rod (2) stretches enough so that flange B contacts the closed end of the tube at A. Calculate the internal force in bronze tube (1).