7- Goodycar Tires claims that their new all-season tires are expected, on average, to last at least 50,000 miles. A random sample of 81 Goodyear tires was tested, and the results showed X = 48980 miles and s=5000 miles. (15%) a. Construct and interpret a 98% confidence interval for the true mean life of the new Goodyear tires. What is the margin of error ME (sampling error SE) of your confidence interval? b. Based on the interval, do you believe the average Goodyear tire lasts more than 50,100 miles? с. What is the desired sample size if you want to cut your ME (in part a) in half?

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Q: 17. Television Viewing A study of 415 randomly selected kindergarten students showed that they have…

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Q: 15. A random sample of 100 visitors to a popular theme park spent an average of $142 on the trip…

A: SOLUTION: Given average x=142          standard deviation σ=47.5          random sample n=100

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A: 1

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Q: 5. A random sample of 100 visitors to a popular theme park spent an average of $142 on the trip with…

A: solution:- Given data average x=142                  σ=47.5n=100

Q: In 2015, the average duration of long-distance telephone calls from a certain town was 3.9 minutes.…

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Q: In a random sample of 22 ​people, the mean commute time to work was 31.1 minutes and the standard…

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Q: 5) al The owner of a car dealership wanted to determine the average distance a person drives a car…

A: Given, sample mean =14362 sample standard deviation =1359 sample size = 72 confidence interval = 99%

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Q: n 2017, the SAT was scored out of 1600. The average SAT scores among the 925 Texas students who…

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Q: Family Vacation Expenses. A survey conducted by the American Automobile Association showed that a…

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Q: In a study of seventh-grade students, the mean number of hours per week that they watched television…

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Q: 1. A random sample of 12 kindergarten students yielded a mean weight of 26kg with sample standard…

A: Given that  1. A random sample of 12 kindergarten students yielded a mean weight of 26kg with sample…