7) Using the Born-Haber cycle and Hess's law, determine the enthalpy of formation for the following overall reaction: Overall reaction: K(s) + 0.5 F2(g) KF (s) Use the energy values below. Keep in mind that all are reported as positive values, but the signs may need to be changed in a given calculation. K(s) K(g) F2(g) F (g) K(g) + F (g) K(g) AH (sublimation) = 89 kJ/mole K(g) AH (ionization) = 418.7 kJ/mole 2 F(g) AH (dissociation) = 159 kJ/mole F (g) AH (electron affinity) = 328 kJ/mole Answer: -553.8 kJ/mole KF(s) AH (lattice energy) = 813 kJ/mole

Chemistry: Principles and Practice
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter5: Thermochemistry
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Problem 5.44QE
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7) Using the Born-Haber cycle and Hess's law, determine the enthalpy of formation for the
following overall reaction:
Overall reaction: K(s) + 0.5 F2(g)
KF (s)
Use the energy values below. Keep in mind that all are reported as positive values, but the signs
may need to be changed in a given calculation.
K(s)
Kg)
F2(g)
F(g)
K + F (g)
+
(g)
Kg) AH (sublimation) = 89 kJ/mole
K(g) AH (ionization) = 418.7 kJ/mole
2 F(g) AH (dissociation) = 159 kJ/mole
F (g) AH (electron affinity) = 328 kJ/mole
Answer: -553.8 kJ/mole
KF (s) AH (lattice energy) = 813 kJ/mole
Transcribed Image Text:7) Using the Born-Haber cycle and Hess's law, determine the enthalpy of formation for the following overall reaction: Overall reaction: K(s) + 0.5 F2(g) KF (s) Use the energy values below. Keep in mind that all are reported as positive values, but the signs may need to be changed in a given calculation. K(s) Kg) F2(g) F(g) K + F (g) + (g) Kg) AH (sublimation) = 89 kJ/mole K(g) AH (ionization) = 418.7 kJ/mole 2 F(g) AH (dissociation) = 159 kJ/mole F (g) AH (electron affinity) = 328 kJ/mole Answer: -553.8 kJ/mole KF (s) AH (lattice energy) = 813 kJ/mole
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