7. according to the reaction: 238 234 4 U Th+ He 92 90 2 A uranium nucleus undergoes alpha decay Take the masses to be 234.043680 u for Th and 4.002603 u for He. The mass for the uranium nucleus is 238.050788 Find the difference in mass between the initial nucleus and the final products, in u. Then use 931 Mev/u to get your answer in energy units Mev. This is the nuclear energy released in the reaction and helps explain both fission and fusion nuclear reactions.

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Chapter26: Relativity
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7.
according to the reaction:
238
234
4
U
Th+
He
92
90
2
A uranium nucleus undergoes alpha decay
Take the masses to be 234.043680 u for Th and 4.002603 u for He.
The mass for the uranium nucleus is 238.050788
Find the difference in mass between the initial nucleus and the final
products, in u. Then use 931 Mev/u to get your answer in energy units
Mev. This is the nuclear energy released in the reaction and
helps explain both fission and fusion nuclear reactions.
Transcribed Image Text:7. according to the reaction: 238 234 4 U Th+ He 92 90 2 A uranium nucleus undergoes alpha decay Take the masses to be 234.043680 u for Th and 4.002603 u for He. The mass for the uranium nucleus is 238.050788 Find the difference in mass between the initial nucleus and the final products, in u. Then use 931 Mev/u to get your answer in energy units Mev. This is the nuclear energy released in the reaction and helps explain both fission and fusion nuclear reactions.
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