7. Draw the HOMO and LUMO -molecular orbitals of 1,3-butadiene. Show/explain why a [4+4] reaction does not occur without the absorption of light. ( ) [4+4]
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- Draw a molecular orbital picture for the LUMO of 1,3-ButadieneIs the molecular orbital diagram of 1,3-butadiene the same as cyclopenta-1,3-diene? If so how come? Doesn't the latter have 5 p orbitals or will it technically only have 4?Which one of the following represents the HOMO of 1,3-butadiene in the ground State?
- What is the total number of nodes in the c3 and c4 MOs of 1,3-butadiene?What is the best way to draw a molecular orbital diagram for 1,3-cyclopentadiene, identifying the Lowest unoccupied molecular orbital and the highest occupied molecular orbital?Answer the following questions for the molecular orbitals (MOs) of 1,3,5,7-octatetraene: a. How many MOs does the compound have? b. Which are the bonding MOs, and which are the antibonding MOs? c. Which MOs are symmetric, and which are antisymmetric? d. Which MO is the HOMO and which is the LUMO in the ground state? e. Which MO is the HOMO and which is the LUMO in the excited state? f. What is the relationship between HOMO and LUMO and symmetric and antisymmetric orbitals? g. How many nodes does the highest-energy MO of 1,3,5,7-octatetraene have between the nuclei?
- Draw the p-molecular orbitals for the LUMO of butadieneMolecule C shown below contains a group called an allene. An allene has the structure of one central carbon being doubly bonded to two other carbons (C=C=C). Please draw out all of the p-orbitals that are involved in the pi-system for molecule C. b) The p-orbital on carbon 1 in molecule C are not in conjugation with the p-orbital on carbon 2 (ie the p- orbitals are not pointing in the same direction and there is no overlap). Why does this happen?What is the thermodynamic product obtained from the addition of 1 equivalent of HBr to 1,3-butadiene?
- The pentadienyl radical, H2C“CH¬CH“CH¬CH2#, has its unpaired electron delocalized over three carbon atoms.(a) Use resonance forms to show which three carbon atoms bear the unpaired electron.(b) How many MOs are there in the molecular orbital picture of the pentadienyl radical?(c) How many nodes are there in the lowest-energy MO of the pentadienyl system? How many in the highest-energy MO?(d) Draw the MOs of the pentadienyl system in order of increasing energy. (continued)762 CHAPTER 15 Conjugated Systems, Orbital Symmetry, and Ultraviolet Spectroscopy(e) Show how many electrons are in each MO for the pentadienyl radical (ground state).(f) Show how your molecular orbital picture agrees with the resonance picture showing delocalization of the unpairedelectron onto three carbon atoms.(g) Remove the highest-energy electron from the pentadienyl radical to give the pentadienyl cation. Which carbon atomsshare the positive charge? Does this picture agree with the resonance picture?(h) Add an…The pentadienyl radical, H2C“CH¬CH“CH¬CH2#, has its unpaired electron delocalized over three carbon atoms.(a) Use resonance forms to show which three carbon atoms bear the unpaired electron.(b) How many MOs are there in the molecular orbital picture of the pentadienyl radical?(c) How many nodes are there in the lowest-energy MO of the pentadienyl system? How many in the highest-energy MO?(d) Draw the MOs of the pentadienyl system in order of increasing energyHow would you develop a molecular orbital for a structure like buta-2-diene that has an anion on the first carbon and a cation on the fourth carbon? Also, how would MO look like for 2-dimethyl-1,3-pentadiene?