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- 7.1 To measure the mass flow rate of a fluid in a laminar flow through a circular pipe, a hot-wire-type velocity meter is placed in the center of the pipe. Assuming that the measuring station is far from the entrance of the pipe, the velocity distribution is parabolic: where is the centerline velocity (r = 0), r is the radial distance from the pipe centerline, and D is the pipe diameter. Derive an expression for the average fluid velocity at the cross section in terms of and D. (b) Obtain an expression for the mass flow rate. (c) If the fluid is mercury at , D = 10 cm, and the measured value of is 0.2 cm/s, calculate the mass flow rate from the measurement.A rocket is fired at an angle of 30° above the horizontal. If the x-component of its initial velocity is vix = 326 m/s, what is the y-component of its initial velocity ? ( vy =?) (Take g = 10 m/s²). (A)188.2 m/s (B) 376.4 m/s (C) 330 m/s (D)250 m/s (E) 163 m/sA ball (2 kg) moves with a speed 6 m/sec, the required force to stop the ball in 7*10-4 sec equals to
- The marketing research department of a large manufacturing company has determined that the demand equations for two major items it produces are given by p = 2,000 - 5x + 8y and q = 4,000+ 9x - 7y where p is the price of item A. is the price of item B , x is the monthly demand for item A , and y is the monthly demand for item B. Find the total monthly revenue from items A and B when x = 15 and y = 5 .Angular Impulse and Momentum Principles To apply the principle of angular impulse and momentum to describe a particle's motion. The moment of a force about a point O, fixed in an inertial coordinate system, MO, and the angular momentum about the same point, HO, are related as follows: ∑MO=H˙O where H˙O is the time derivative of the angular momentum, HO=r×mv. Integrating this equation with respect to time yields the following equation: ∑∫t2t1MO dt=(HO)2−(HO)1 This equation is the principle of angular impulse and momentum, and it is often rearranged to its more familiar form (HO)1+∑∫t2t1MO dt=(HO)2 A centrifugal governor consists of a central rotating shaft that has two thin, pin-connected rods attached to it; a heavy sphere caps the end of each rod. (Figure 1) A centrifugal governor mechanically limits an engine's speed. A part of the engine turns the centrifugal governor, and if the speed exceeds a set amount, the height of the spheres decreases the driving force of the engine by…Angular Impulse and Momentum Principles To apply the principle of angular impulse and momentum to describe a particle's motion. The moment of a force about a point O, fixed in an inertial coordinate system, MO, and the angular momentum about the same point, HO, are related as follows: ∑MO=H˙O where H˙O is the time derivative of the angular momentum, HO=r×mv. Integrating this equation with respect to time yields the following equation: ∑∫t2t1MO dt=(HO)2−(HO)1 This equation is the principle of angular impulse and momentum, and it is often rearranged to its more familiar form (HO)1+∑∫t2t1MO dt=(HO)2 A centrifugal governor consists of a central rotating shaft that has two thin, pin-connected rods attached to it; a heavy sphere caps the end of each rod. (Figure 1) A centrifugal governor mechanically limits an engine's speed. A part of the engine turns the centrifugal governor, and if the speed exceeds a set amount, the height of the spheres decreases the driving force of the engine by…
- A 26-pound weight stretches a certain spring 2 feet when the weight and spring are placed in a fluid that resists motion with a force equal to four times the speed. If the weight is stopped at the equilibrium position and then given a velocity of 5 ft / s, find the equation of motion. The DE that models this phenomenon is y "+ Xy '+ (p/l)y = 0, where X is the resistance force of the medium, p is the weight and l the stretch it produces in the spring.1) Is it possible to prescribe the velocity v0, so that the pendulum keeps rotating with alpha = pi/2 Explain clearly why? Given: L, g, and m. 2) After transient motion, the pendulum settles at steady state rotation atalpha = pi/3. Find the initial velocity v0. Given: L, g, m, sin(pi/3) = (squareroot(3)/2), cos(pi/3) = (1/2). [Hint: Use the conservation of energy and the 2nd Newton’s law.]An object of mass m=2kg is part of a system and it is subject only to conservative forces and constrained to move along a horizontal line such that the potential energy of the system is given by the function U(x)=(−10)/(x2+1), where x is in meters and U is in joules. The graph of the function is shown in the image. (e) Another object is subject only to a different set of conservative forces and constrained to move along a horizontal line such that its potential energy is given by a different function U(x). Explain how the new function U(x) could be used to locate a point of stable equilibrium.
- The shaft of a turbine rotor, initially at rest, accelerates uniformly for 0.9s at 25 rad/s2. Compute and identify the nearest value of the angle turned through by the shaft in degrees during this time. a. 960o b. 580o c. 645o d. 720o Clear my choicePrinciple of Linear Impulse and Momentum for a System of Particles To apply the principle of linear impulse and momentum to a system of particles. Integrating the equation of motion, as applied to all particles in a system, yields ∑mi(vi)1+∑∫t2t1Fidt=∑mi(vi)2 where mi is the ith particle's mass, vi is the ith particle's velocity, and Fi is the external force that acts on the ith particle. This relationship states that the sum of the initial linear momenta, at time t1, and the impulses of all the external forces acting between times t1 and t2 is equal to the sum of the linear momenta of the system, at time t2. If the system has a mass center, G, the expression becomes m(vG)1+∑∫t2t1Fidt=m(vG)2 This expression allows the principle of linear impulse and momentum to be applied to a system of particles that is represented as a single particle. Two blocks, each of mass m = 6.90 kg , are connected by a massless rope and start sliding down a slope of incline θ = 36.0 ∘ at t=0.000 s. The…This most likely is made to be a probelm about mx''+bx'+kx=f(t) m = mass b = friction k = spring constant 4. A mass weighing four pounds stretches a spring 24 in. Suppose the mass is atequilibrium and is set into motion with a velocity of 6 inches per second. The mass is in a mediumwhere friction is small, and we assume it is zero. Note that the acceleration due to gravity near theearth’s surface where the experiment takes place can be taken as 32 ft/s2.(a) Suppose that in addition to the conditions described above, a hammer strikes the mass everyπ/2 seconds starting at t = 0. A delta function with impulse of 1 pound-second models theforce of each blow to the mass. Find the function x(t) for the displacement from equilibrium infeet of the mass at time t in seconds. Express x(t) as a piecewise defined function without the use ofunit step or Heaviside functions and such that in each time window it is a different multiple of the samesinusoidal function.(b) Now assume the same spring-mass…