7. Tooth enamel (Cas(PO4)3OH) is a slightly soluble compound that exists as the equilibrium shown below. If the Ksp of tooth enamel in water is 6.8 x 10-37 calculate the molar solubility of tooth enamel. Cas(PO4)3OH (s) → 5Ca²+ (aq) + 3PO4³ (aq) + OH- (aq) a. 2.7 x 105 M b. 5.84 x 108 M C. 8.2 x 10-19 M d. 6.4 x 10⁹ M 2.00

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Chapter12: Chemical Equilibrium
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CS 10 nousT200
7. Tooth enamel (Ca5(PO4)3OH) is a slightly soluble compound that exists as the equilibrium shown
below. If the Ksp of tooth enamel in water is 6.8 x 10-37 calculate the molar solubility of tooth
enamel.
a.
b.
2+
3-
Cas(PO4)3OH (s) → 5Ca²+ (aq) + 3PO4 (aq) + OH- (aq)
2.7 x 105 M
5.84 x 10-8 M
C.
8.2 x 10-¹9 M
d. 6.4 x 109 M
2.00
Transcribed Image Text:CS 10 nousT200 7. Tooth enamel (Ca5(PO4)3OH) is a slightly soluble compound that exists as the equilibrium shown below. If the Ksp of tooth enamel in water is 6.8 x 10-37 calculate the molar solubility of tooth enamel. a. b. 2+ 3- Cas(PO4)3OH (s) → 5Ca²+ (aq) + 3PO4 (aq) + OH- (aq) 2.7 x 105 M 5.84 x 10-8 M C. 8.2 x 10-¹9 M d. 6.4 x 109 M 2.00
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