7. username_ends_with_digits This function decides whether a given username ends with some digits. It returns either True, if the username does end with digits, or False, if it does not. Check out the .isdigit method on strings! Sample runs should look like: >>> username_ends_with_digits("FunctionEnjoyer") False >>> username_ends_with_digits("this_username_95060") True
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- A Millenial is someone born between 1981 and 1996 (inclusive). Using boundary analysis write test cases to test the IsMillenial function: public bool IsMillenial(int year) that takes a year of birth (in the Gregorian Calendar) and returns true if the person is a millenial and false if it isn't. If the year is not a valid Gregorian Calendar year then the function throws ArgumentOutOfRangeException. Note: There is total of 13 test cases. using Microsoft.VisualStudio.TestTools.UnitTesting; using System; using System.Collections.Generic; [TestClass] public partial class { // Your code starts here // Your code ends here }C++ This is what i have as a solution. Can you check If this makes sense according to the question if yes is there any logic errors. Are the functions doing what is said in the question. A. ~Train() { Car* current = tHead; for (int i = 0; current != NULL; i++) { Car* next = current->nextCar; delete current; current = next; } } B. void removeFirstCarOfType(const std::string& name) { if (tHead == NULL) { return; } Car* temp = tHead; if (temp->getName() == name) { tHead = temp->nextCar; free(temp); return; } int pos = 0; for (int i = 0; temp != NULL; i++) { if (temp->getName() == name) { pos = i; break; } temp = temp->nextCar; } if (temp == NULL || temp->nextCar == NULL) { return; } temp = tHead; for (int i = 0; temp != NULL && i < pos - 1; i++) { temp =…Write a function named validate that takes code represented as a string as its only parameter. Your function should check a few things: the code must contain the def keywordotherwise return "missing def"the code must contain the : symbolotherwise return "missing :"the code must contain ( and ) for the parameter listotherwise return "missing paren"the code must not contain ()otherwise return "missing param"the code must contain four spaces for indentationotherwise return "missing indent"the code must contain validateotherwise return "wrong name"the code must contain a return statementotherwise return "missing return"If all these conditions are satisfied, your code should return True. Here comes the twist: your solution must return True when validating itself.
- Question 12 kana .Which of the following statements is false? The re module's findall function finds every matching substring in a string and returns a list of the matching substrings. The following code extracts all phone numbers of the form ###-###-#### from a string:contact = 'Wally White, Home: 555-555-1234, Work: 555-555-4321're.findall(r'\d{3}-\d{3}-\d{4}', contact) The re module's finditer function works like findall, but returns a greedy iterable of match objects. For large numbers of matches, using finditer can save memory because it returns one match at a time, whereas findall returns all the matches at once. Full explain this question and text typing work only We should answer our question within 2 hours takes more time then we will reduce Rating Dont ignore this linePlease help me with this task. Thank you! public class CustomString { String myString; boolean isSet; public CustomString() { this.myString = null; this.isSet = false; } /** * Returns a new string version of the current string where the alphabetical characters specified in the given arg, are removed. * * The alphabetical characters to be removed are case insensitive. * All non-alphabetical characters are unaffected. * If the current string is null, empty, or has not been set to a value, this method should return an empty string. * * Example(s): * - For a current string "my lucky numbers are 6, 8, and 19.", calling remove("ra6") would return "my lucky numbes e 6, 8, nd 19." * - For a current string "my lucky numbers are 6, 8, and 19.", calling remove("6,.") would return "my lucky numbers are 6, 8, and 19." * - For a current string "my lucky numbers are 6, 8, and 19.", calling remove("") would return "my…Write a function named “hasDashOnBothSides” that accepts parameters of the same as command line arguments (argc and argv). It returns true if all of the arguments have a '-' on both the beginning and ending of the arguments and false otherwise. If it has no argument, it will return true. In addition, this function also returns another boolean value of true when one of the arguments is just a dash ('-') and false otherwise. Please note that you cannot use string class, string methods such length() or size() or any string function such as strlen(). Please use only array notation, pointer to character, and/or pointer arithmetic and make use of the fact that this is a C-string. Please show how you would call and test this function. One simple way is to accept command line arguments or the other is to simply hard-code values of the array and call this function. Please print out the results of what this function returns. If there is no argument, it will return true and false If the argument…
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- It says there is an error in the class solution(the followup one), specifically in the read data function students[i].setGrade(); It says it is empty, but when I add the declaration char grade; to the function and change the statement to students[i].setGrade(grade); it still says there is an error. What does it need to be instead? Here is my code: #include <iostream> #include <string> using namespace std; const int numstudents = 20; class studentType { private: string studentFName; string studentLName; int testscore; char grade; public: void setName(string first, string last) { studentFName = first; studentLName = last; } void setScore(int score) { testscore = score; } void setGrade(char grade) { if (testscore >= 90) { grade = 'A'; } if (testscore <= 90 && testscore >= 80)…Write a function called isVowel that receives one parameter as character and returns true ifit is a vowel (A, E, I, O, U) letter. Write another function called replaceV that receives two parameters as string(parameter1) and character (parameter2) and returns a new string that replaces all the vowel letters fromparameter1 with parameter2. The replaceV function should use isVowel function to check each character inthe string.Write a test program that reads a string and a character and uses replaceV to get the new string then displaysthe new string. Here is a sample run:Enter a String: Hello world!Enter a character: $The new string is: H$ll$ w$rld!I have problem in java 2 code: lease.setApartmentNumber(sc.nextLine()); melt:String cannot be converted to int and lease.setMonthlyRent(sc.nextLine()); melt introduce variable and lease.setPeriod(sc.nextLine()); melt: introduce variable System.out.println("Tenant's Name"+lease.getTenantName()+"\nApartment Number:"+lease.getApartmentNumber()+"\nMonthly Rent:"+NumberFormat.getCurrencyInstance().format(lease.getMonthlyRent())+"\nTerm of lease in month;"+lease.getPeriod());} melt: create Object getMonthlyRent() Java 1: package lease; public class Lease { private String tenantName;private int apartmentNumber;private double monthlyRent;private int Period; public Lease() {apartmentNumber = 0;int monthlyRent = 10000;int Period = 12; } // Getter Methodpublic String getTenantName() {return tenantName;} public void setTenantName(String tenantName) { this.tenantName = tenantName;} public int getApartmentNumber() {return apartmentNumber;} public void setApartmentNumber(int…