7. When the given differential equation is Solved using Laplace transform Method, the equivalint subsidiary equaton with y (0) =1 and y'(0) =-2is. y"+ ay + y=tet 7. %3D (s?+ 2s +1) y (s) = a- %3D 2. b.(5?+$+1)y(s) = st- (Sti)?

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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7. When
the given differential equation is
Solred using Laplace transform Method, the
equivalint subsidiary equaton with
y (o) =1 and y'c0)ニーマis'
y"+ 2y +y tet
=(5)6 (1+ se t;s)
(S+1)
2.
St.
%3D
(Sti)?
C(5+25 +1)りく)
1-
(st)
-s
d.(st+ 25 +1)y(s)
+ S-4
(St)?
Transcribed Image Text:7. When the given differential equation is Solred using Laplace transform Method, the equivalint subsidiary equaton with y (o) =1 and y'c0)ニーマis' y"+ 2y +y tet =(5)6 (1+ se t;s) (S+1) 2. St. %3D (Sti)? C(5+25 +1)りく) 1- (st) -s d.(st+ 25 +1)y(s) + S-4 (St)?
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