7.07 LE CHATELIER'S PRINCIPLE 75 kJ Potential Energy 65 kJ 230 kJ d B C Reaction Coordinate D N₂ (g) + 3H₂(g) 2NH₂ (g) -AH Increase N2 Increase H2 Increase NH3 Decrease H2 Decrease N2 Decrease NH3 Increase Volume Increase Temp Increase Pressure Decrease Volume Decrease Temperature Decrease Pressure

7.07 LE CHATELIER'S PRINCIPLE 75 kJ Potential Energy 65 kJ 230 kJ d B C Reaction Coordinate D N₂ (g) + 3H₂(g) 2NH₂ (g) -AH Increase N2 Increase H2 Increase NH3 Decrease H2 Decrease N2 Decrease NH3 Increase Volume Increase Temp Increase Pressure Decrease Volume Decrease Temperature Decrease Pressure

Chemistry for Engineering Students

3rd Edition

ISBN:9781285199023

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter11: Chemical Kinetics

Section: Chapter Questions

Problem 11.61PAE

See similar textbooks

Similar questions

At 25 oC an antibody binds a protein with a ∆H = -87.9 kJ/mol and ∆S = -118.9 J mol-1 K-1 Which of the following is/are true? (Choose all that are correct) a. The process is exergonic b. The process is endothermic c. The entropy of the binding process increases d. The binding process is exothermic e. The entropy during the binding process decreases
Given the following data: C2H4(g) + 3O2(g) -> 2CO2(g) +2H2O(l) deltaH = -1411.0 kJ 2C2H6(g) + 7O2(g) -> 4CO2(g) +6H2O(l) deltaH = -3119.8 kJ 2H2(g) +O2 -> 2H2O(l) deltaH = -571.7 kJ Calculate deltaH for the reaction: C2H4(g) + H2(g) -> C2H6(g)
Enter your answer in the provided box. Calculate ΔG Enter your answer in the provided box.4 for the following process at 25°C. BaF2(s) ⇌ Ba2+(aq) + 2F−(aq) The Ksp of BaF2 is 1.7×10−6. ΔGo=___________kJ/mol
The ΔG°’ for binding a substrate to an enzyme is -14 kJ/mol at 25°C. What is the Keq’ for the reaction? R is 8.31 J/mol-K. in 3 sig.figs.
Find DG° for this reaction: CH4 (g) + 2O2(g)+ ---> CO2 (g)+ 2H2O (l) Substance DGfdegree (kJ/mol) CH4(g) -50.66 O2(g) 0 CO2(g) -394.4 H2O(l) -237.4 A –682.5 kJ B 131.1 kJ C –581.1 kJ D -919.9 kJ E -818.5 kJ
List two ways that enzyme catalysis of a reaction is superior to normal conditions.
The standard free energy variation, at 25 ºC, for equilibrium: Glucose-6-phosphate (G-6-P) Glucose-1-phosphate (G-1-P) is ΔGº '= + 7280 J / mol. Calculate a) The equilibrium constant of the reaction. b) The real change in free energy when one mole of G-6-P is transformed into G-1-P, both concentrations remaining constant and equal to 10mM and 2 mM respectively.
Calculate delta H for the following rection, FeO + CO = Fe + CO2 from the following data: Fe2O3 + 3CO --> 2Fe +3CO2 Delta H= -23 kJ 3Fe2O3 + CO --> 2Fe3O4 +CO2 Delta H= -39 kJ Fe3O4 +CO --> 3FeO +CO2 Delta H= +18 kJ
Use the standard reaction energies given below to determine DeltaG^°rxn for the following reaction: 2XO2(g) —> 2XO(g) + O2(g) From the standard reaction energy of X2(g) + O2 —> 2XO(g) DG^°= 155.52 Kjxmol-1 X2(g) + 2O2 —> 2XO2(g) DG^°= 168.55 Kjxmol-1 Given answer in Kj/mol. Give answer to two decimal places.
Every valentine’s day, CVS sells chocolate-covered cherries. The chocolate-covered cherries are like a mini cake with a cherry inside. The cake comprises a combination of sucrose (powder sugar), butter, cherry juice, and an enzyme (invertase). Time (hours) Sucrose Concentration (g/cm3) 0 0.844 24 0.681 48 0.550 96 0.357 192 0.153 While stored at 5.00C, the sucrose hydrolyzes to produce glucose and fructose. The mixture of the glucose and fructose is a liquid called invert sugar. Below you will find the concentration of sucrose in the cake as a function of time. For the cherries to be edible, the 85% of the sucrose must be hydrolyzed. Before you start to answer the question, create a data table that comprises sucrose concentration in units of moles per liter. Write the chemical reaction that demonstrates the hydrolysis of sucrose. With the data, determine how long it will take for 85% of the sucrose to be converted into…
Succinate is the substrate for succinate dehydrogenase that converts succinate to fumarate. In the presence of reversible competitive inhibitor like malonate in place of succinate, the enzymes a) Km increases and Vmax remains the same. b) both Km and Vmax increases. c) both Km and Vmax decreases. d) Km decreases and Vmax remains the same.
Given ΔHoformation, (CO2(g)) = -395,51 kJ/mol ΔHoformationCp(CO2) = 37.11J/Kmol-1, ΔHoformationCp(O2) = 29.355 J/Kmol-1, and ΔHoformationCp(C) = 8.527J/Kmol-1, T2 = 125o, T1 = 20oC. Find ΔH2o for the reaction: C(s) + O2(g)-à CO2(g), when Cp is independent of T.