Can you please explain this to me step by step? And how to read na formula and the given, all you have to do is discuss, it has an answer already, it's really short problem, Thank you in advance, I really need ittoday... 7.5 UNKNOWN PERIODIC PAYMENTSOften, in a given problem, the present or future value, the interest rate and the number of periods areknown and the size of the annuity is unknown. To determine the size of an annuity is to find the periodicpayment.Example 9. What monthly payment is needed to accumulate 10,000 due after 2 years at 10%?Solution: Given: (general ordinary annuity) S = 10,000, t = 2 years, i = 10%, p = 1, c = 12, k = 1/12Since the annuity is a general ordinary annuity and the given is the accumulated value then theSniS =Rformula to be used isR = SSmi$1,20.10R = 10000Sz10.10|(1.10)/12 -10.10R = 10000(1.10)? – 10.10(1.10)/12 –1(1.10)² – 1R = 10000R = 379.7210000 x ( 1.10 ^ (1+12) - 1 ) +( 1.10 ^ 2 - 1) = 379.72

Given that the accumulated value of an unknown monthly payment after 2 years is 10000 at 10% per…

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

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Can you please explain this to me step by step? And how to read na formula and the given, all you have to do is discuss, it has an answer already, it's really short problem, Thank you in advance, I really need it today...

7.5 UNKNOWN PERIODIC PAYMENTS
Often, in a given problem, the present or future value, the interest rate and the number of periods are
known and the size of the annuity is unknown. To determine the size of an annuity is to find the periodic
payment.
Example 9. What monthly payment is needed to accumulate 10,000 due after 2 years at 10%?
Solution: Given: (general ordinary annuity) S = 10,000, t = 2 years, i = 10%, p = 1, c = 12, k = 1/12
Since the annuity is a general ordinary annuity and the given is the accumulated value then the
Sni
S =R
formula to be used is
R = S
Smi
$1,20.10
R = 10000
Sz10.10
|(1.10)/12 -1
0.10
R = 10000
(1.10)? – 1
0.10
(1.10)/12 –1
(1.10)² – 1
R = 10000
R = 379.72
10000 x ( 1.10 ^ (1+12) - 1 ) +( 1.10 ^ 2 - 1) = 379.72

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