79. In the diagram, PQU is an equilateral triangle, QRVU is a rectangle and RSTU is a 'rhombus. The area of rectangle QRVU is 12 cm². 4cm 5cm R Find the perimeter, in cm, of the whole diagram. (1) 17 (2) 21 (3) 26 (4) 30

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79. In the diagram, PQU is an equilateral triangle, QRVU is a rectangle and RSTU is a 'rhombus. The area
of rectangle QRVU is 12 cm².
4cm
5cm
R
Find the perimeter, in cm, of the whole diagram.
(2) 21
(3) 26
(1) 17
80. The diagram shows two rectangle, PQRS and KLMN.
(4) 30
R
2cm
N
1cm
lcm
6cm
2cm
10 cm
The perimeter, in cm, of the shaded area is
(1) 32
(2) 28
(3) 20
(4) 16
81. In the diagram, PQRS is a rectangle.
4y ст
IS
Зх ст
2у ст
x cm
R
After the shaded rectangle is removed, the area, in cm2, of the remaining portion is
(4) 2y - 2x
(1) 5ху
(2) 10xy
(3) 5x + 6y
Transcribed Image Text:79. In the diagram, PQU is an equilateral triangle, QRVU is a rectangle and RSTU is a 'rhombus. The area of rectangle QRVU is 12 cm². 4cm 5cm R Find the perimeter, in cm, of the whole diagram. (2) 21 (3) 26 (1) 17 80. The diagram shows two rectangle, PQRS and KLMN. (4) 30 R 2cm N 1cm lcm 6cm 2cm 10 cm The perimeter, in cm, of the shaded area is (1) 32 (2) 28 (3) 20 (4) 16 81. In the diagram, PQRS is a rectangle. 4y ст IS Зх ст 2у ст x cm R After the shaded rectangle is removed, the area, in cm2, of the remaining portion is (4) 2y - 2x (1) 5ху (2) 10xy (3) 5x + 6y
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