8) (2,-9), (-1, 4) 13.3 (10) (8, 5). (-1,3) 9.2 (2) (-6,-10), (-2,-10) 4

Q: |(-3,3) (-3, 2) -3,2) -6 -5 -4 -3 -2 -1, V 2 3 4 5 6 7 -2

A: Standard form of parabola isy=ax2+bx+c

Q: 10- 8- 6- 2- -10. -8. -6. -4 -2 2. 6. 8. -2- 4. 4.

A: Given the graph of F(x) And G(0)=0

Q: -6 -5 -4 -3 -2 -1 5 4 -3 A 2 -1- 0 --1- -2 -3- -4 -5- 2 3 4 5

A:

Q: 19. (- 4,– 6)

A:

Q: 6- 5 3. 2+ -7-6 5 -4-32 2 3 4 5 6 7 4 -5- -6-

A: Solution of this question is

Q: (-3,9) 12 (6,6) (-2,6) -6,0) -2 (0,-3) 9- (2,-6) -6 -4 2. (4,0) -7,-6) -12 -

A: Given that: Graph of f(x)

Q: 3. {(-1, 1, 2), (2, –3, 1), (10, –14, 0)}

A:

Q: As per attachment ,Which two vectors are parallel?

A: v1=4, 6,  v2=-3, -6,  v3=-8, 4  &  v4=10, 15.

Q: 5+ 4 -5 -4 -3 -2, /-1 I 2 3 4 5 -2 -3-

A: Follow the next step

Q: (-7,0) and (-2,4) (5,9) and (-7,-7) (4,6) and (-4,-3) (-6,-10) and (-2,-10)

A: we know that, distance between two points(x1,y1) and (x2,y2) is, distance = ( (x2-x1)2 - (y2-y1)2…

Q: 5+ 4 4 -3 -2/-1 1 2 3 4 5 -2- -3 -4 -5+

A:

Q: (4-31)-(-a+3:)

A:

Q: y = -4x - 3 X y -4 -2 6. -6 -8 O -2, 8, 2, 10, 6 O -42, -38, -22, 18, 10 O 24, -16, -32, 16, 56 13,…

A:

Q: 10 -10 -8 -6 -4 -2 2 4 8, 10 -2 -4 -6 -8 -10 6. 6, 4.

A:

Q: -8- 7 -6 3 2- 4 5 6 7 -4 -3 -2 -1 0 -1- -8 -7 -6 -5 2 -3 4- -5 -6- -7- --8- 3- 2.

A: The equation of a circle with center at (a,b) and radius r is given by, x-a2+y-b2=r2

Q: (4,6) V2 = (-3, -6) V3 = (-8, 4) V4 = (10, ニ

A:

Q: -7 3 -10 -9 -8 -7 -6 -5 -4 -2 5 6. 8. 10 -7 9. 7. 3. 2. 1, 2.

A:

Q: 4+ 2 9- -4 -2 2 4 6 2 -4- 6+

A:

Q: 6- (2,4) (5,3) 3- (4,2) (6,1) 4 8.

A: To find:-   from using given graph Absolute maximum Absolute minimum Local maximum

Q: 7. (-1, -4), (0,7) 8. (1,1/2), (1/2,-2) 9. (0,-12), (-6,0) 10. (-4.5, -3.5), (7.5, -5.5)

A:

Q: 2, 3, .. ,0, 1, 2, 3, ...

A:

Q: (-2, 4) 5- (-5, 2 (-1,1) -5 (0, 0) (G1, –1) -4, -5 (–2, –5) LO

A:

Q: -9 8 -7 -6 -5 -4 -3 -2 -1 0 --1- --2 -3 -4 -5 -6 2/5 1.

A:

Q: (-2, 40) 40 (-7, 0). (0, 0) -5 -3 -1 -16 (-4, 0).

A:

Q: a.) (2,3), (5, 7), (-3, 4) .) (5, 3), (2,0), (2,6) c.) (2,6), (-3,3), (5,2)

A: Since you have Posted a question with multiple sub-parts, we will solve the first three sub-parts…

Q: What is the standard form of the equation of the circle?

A: Center of the circle is =(h,k)= (2,-8) Radius of the circle = r = 1

Q: -3 -3 2 -5 9 -3 -2 2 = 4X – 3 8 - -7 -8

A:

Q: `-10 -9 -8 -7 -3 -2 -1 1 2 3, 4 5 6 7 8 9 10 -1 -2 -3 -6 -7 -8 -9 -10

A:

Q: 25. у" - 2у' + у 3 21- 3, y(0) = 5, y'(0) = 11

A:

Q: 5. 4. 3 2- -6 -5 -4 -3 -2 -1 -1 3. -2- -3 -4 - -5+

A: Concept - with the help of graph of Tanx

Q: 5) 8.2.-4,-10, B. Given the gener Rule term

A: Note :-According to company policy we can attempt ?️ only one question so please upload the next…

Q: -1 5 3 -6 3 2 -1 1 -5 -3 6, 5.

A: Given matrix is A=−1563−632−151−5−3 To find the

Q: ( -7) and (9, 5) 2,5), (9,

A:

Q: (-5,3)and(-1,0)

A: Topic:- geometry

Q: (-5) + 4 – 1+ 4- (-21) * (-7)) ova

A: Simplification

Q: 5- 4 3 న్ -- /-3 -2 1 2 3 4 5 -2 -3

A:

Q: 5+ -5 -4-3 2 -1 2 3 4 5 -2 -3- -4 -5+ 3.

A:

Q: (2, 3, 0), B(-2, 3, 0), C(0, 0, 0)

A:

Q: 4- 3. -5 -4 -3 -2 -1 4 -2 -3 -4 - -5- 3. 2.

A:

Q: 8. 9. y 2 (2, 2) Е3, 4) -4 -2 2 4 |-4 -2 0 6. (-1, –4), 2 (3, –1) 4, 4-

A:

Q: 10- 8- 6- 4- 2- -8 -4 -2 10 2- 4- -6- 40

A: Draw a graph.

Q: 4 3+ 2+ 1+ f 个十 -7 -6 -5 -4 -3 -2 12 34 5 6 7 -2+ -3+ -4-

A:

Q: 3. (-8, -7) and (-1, -1} 21. (2,-8) and (S, -6) 8. (-6, 3) and (5, 6)

A: As per the company rule, we are not supposed to solve only three subparts of a multipart problem.…

Q: 7- 4- 2 -8 -7 -6 -5 -4 -3 -2 -1 I 2 5 6 7 -2 -3 -4 -5 -7 6

A: here equation is given  by y=4ax^2 vertex at (3,-1) than  x=a(y-3)^2-1 now x intercept is (5,0) that…

Q: السؤال الثاني أثبت باستخدام المتجهات ان النقاط )2,0- A(0, ,2-)C -2,-2), B(-2,0, -2), تمثل رؤوس مثلث…

A:

Q: = (2,1,0,3), v2 (0,1,5,7), v3 = (0,0,3, –1), v4 = (0,0,0, –4) b) V1

A:

Q: -6 -5 -4 -3 -2 -1 0 2 3 4 --1- -2 -3 -4 -5- -6 -7

A: Topic - circles

Q: (8,3,-2), (5,8,-6), (-7,2,-1)

A: