8 6. -3 -2 -1 1 4 2.

College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter3: Functions
Section3.7: Inverse Functions
Problem 2SE: Why do we restrict the domain of the function f(x)=x2 to find the function's inverse?
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1d. 1e.

For questions 1 and 2, consider the function f(x) = ÷x2.
+ x +1 on the interval [0, 4].
12
10
8
6.
4
2
2
1
2
3
4
Transcribed Image Text:For questions 1 and 2, consider the function f(x) = ÷x2. + x +1 on the interval [0, 4]. 12 10 8 6. 4 2 2 1 2 3 4
d)
Is this area approximation going to be an overestimate or an underestimate. Explain.
e)
Calculate this area approximation.
Area Approximation
Transcribed Image Text:d) Is this area approximation going to be an overestimate or an underestimate. Explain. e) Calculate this area approximation. Area Approximation
Expert Solution
Step 1: Here we have given with function f(x) = (1/4)x^2+x+1 on the interval (0,4)

We have to determine whether it is underestimate or overestimate.

We know that, if the graph is concave down(second derivative is negative) then the line will lie above the graph

and the approximation is an overestimate, otherwise it is underestimate.(simply if the graph is concave up).

d) Here from graph we can easily observed that the graph of f(x) = 14x2+x+1,  on [0,4]    given above is

concave up on [0,4]. So the area approximation for this graph going to be an overestimate.

e) Now we have to calculate this area approximation.

We know the graph of f(x) given above is increasing on the interval [0,4], then the left sum is an

underestimate of the actual value and the right sum is an  overestimate.

 

Step 2

Therefore, we need to calculate right sum because our area approximation here for given function is overestimate.

Let us divide given interval [0,4] in 4-equal rectangles.

So length of each rectangle is  4-04=1 unit,

So the right end points are  0+i1  = i, where i{1,2,3,4}

Hence, 

                           

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