8- Arrange the following compound according in increasing melting point: KCI, He , H2O, HF A) Kcl > HF > H2O > He B) H2O > HF > KCl> H C)) HF > H2O>KCl> He D) KCI > H20 > HF > He
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8- Arrange the following compound according in increasing melting point:, explain please
KCl, He, H₂O, HF
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- Solution:- 3. Determine the amount, in of a (2.20 M s olution of dichloromethane needed to completely react with 15.72g cyclohexene to give 1,2-dibromocuclohexanw. Assume 12% excess is needed in order to react completely. a . How much 1,2 -dibromocyclohexane would theoretically be produced ? c. How many ML of the 2.20 M Br2 solution are required?Any special precautions or purifications of the reagents required? Limiting and excess reagent? Why is excess necessary? 4,4'-DIBROMOBIPHENYL [Biphenyl, 4,4'-dibromo-] Submitted by Robert E. Buckles and Norris G. Wheeler1. Checked by R. S. Schreiber, Wm. Bradley Reid, Jr., and Robert W. Jackson. 1. Procedure In a 15-cm. evaporating dish is placed 15.4 g. (0.10 mole) of finely powdered biphenyl (Note 1). The dish is set on a porcelain rack in a 30-cm. desiccator with a 10-cm. evaporating dish under the rack containing 39 g. (12 ml., 0.24 mole) of bromine. The desiccator is closed, but a very small opening is provided for the escape of hydrogen bromide (Note 2). The biphenyl is left in contact with the bromine vapor for 8 hours (or overnight). The orange solid is then removed from the desiccator and allowed to stand in the air under a hood for at least 4 hours (Note 3). At this point, the product weighs about 30 g. and has a melting point in the neighborhood of 152°. The crude…CH.8 #8 - Please fill in the blank, cirlce your answer for thumbs up!
- Consider the compounds 1-pentanol,CH3-CH2-CH2-CH2-CH2-OH, melting point -78C boiling point 138C, MW=88.15. 1,6-hexanediol ,HO-CH2-CH2-CH2-CH2-CH2-CH2-OH, mp 42C,bp=250C.MW=118.18. The compound 1,6-hexanediol is more soluble in water than 1-pentanol is. This is because 1,6-hexanediol.... 1) has more carbon atoms 2)has a higher molecular weight 3)has more -OH groups 4)is a solid at room temperatureIn the following cases rearrange the compounds as directed : (Delhi 2010)(i) In an increasing order of basic strength :C6H5NH2, C6H5 N(CH3)2, (C2H5)2NH and CH3NH2(ii) In a decreasing order of basic strength :Aniline, p-nitroaniline and p-toluidine(iii) In an increasing order of pKb values :C2H5NH2, C6H5 NHCH3, (C2H5)2NH and C6H5NH2percentage recovery of benzoic acid is 77.18%. The melting point range of crude benzoic acid = 112-119°C and the melting point range of pure benzoic acid (crystals) = 122-125. Comment on the percentage recovery of benzoic acid. Comment and compare the melting point of the crude and crystal samples
- The separation and purification processes given below and the method used against them are given. Which or which of these pairings are correct? I. Brewing of tea - ExtractionII. Purification of water impurities - ChromatographyIII. Separating olive pomace from olive oil while producing olive oil-DecantationIV.Petroleum fractions obtaining - Ordinary distillationV. Obtaining essential oils and using them in perfume making - Water-steam distillationA. I, II, III, IVB. I, II, III, IV, VC. I, IV, VD. I, II, III, VE. I, II, V1. Which of the following compounds can form hydrogen bonds with water?a. octaneb. HClc. NaCld. acetic acid2. Maria wants to determine the percent water content of an unknown hydrate of AB. Given the following data:mass of empty crucible - 12. 2784gmass of AB · xH20 + crucible - 17.4960gmass of AB + crucible - 15.1314gCalculate the % water content of the hydrate3. From the above data, give the correct formula for the hydrate. (AB₂ Molar mass = 129.84 g/mol)Ksp for Co(OH)2 is 5.92x10^-15