Based on the following values: Mathematical expectation: E(X) = ∑Xn1 = 1204 = 30 E(Y) = ∑Yn2 = 1884 = 47 E(Z) = ∑Zn3 = 1784 = 44.5 Variance: var(X) = 1n1-1∑X2-1n∑X2 = 14-13678-12024 =26 var(Y) = 1n2-1∑Y2-1n∑Y2 = 14-18890-18824 =18 var(Z) = 1n3-1∑Z2-1n3∑Z2 = 14-18322-17824 =133.6667 Root mean square deviation sd(X)= var(X) =26 = 5.0990 sd(Y)= var(Y) =18 = 4.2426 sd(Z)= var(Z) =133.6667 = 11.5614 Correlation coefficients X Y Z     25 44 28   28 43 48   37 49 55   30 52 47 1. Expectation 120 188 178 2. Variance 26 18 133.6667 3. root mean square deviation 5.099 4.2426 11.5614    Check the hypothesis in the image below. The table values are also there

Elementary Algebra
17th Edition
ISBN:9780998625713
Author:Lynn Marecek, MaryAnne Anthony-Smith
Publisher:Lynn Marecek, MaryAnne Anthony-Smith
Chapter2: Solving Linear Equations And Inequalities
Section2.6: Solve A Formula For A Specific Variable
Problem 2.130TI: Solve the formula 5x+8y=1 for y.
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Based on the following values:

Mathematical expectation:

E(X) = ∑Xn1 = 1204 = 30

E(Y) = ∑Yn2 = 1884 = 47

E(Z) = ∑Zn3 = 1784 = 44.5

Variance:

var(X) = 1n1-1∑X2-1n∑X2 = 14-13678-12024 =26

var(Y) = 1n2-1∑Y2-1n∑Y2 = 14-18890-18824 =18

var(Z) = 1n3-1∑Z2-1n3∑Z2 = 14-18322-17824 =133.6667

Root mean square deviation

sd(X)= var(X) =26 = 5.0990

sd(Y)= var(Y) =18 = 4.2426

sd(Z)= var(Z) =133.6667 = 11.5614

Correlation coefficients


X

Y

Z

 

 

25

44

28

 

28

43

48

 

37

49

55

 

30

52

47

1. Expectation

120

188

178

2. Variance

26

18

133.6667

3. root mean square deviation

5.099

4.2426

11.5614

 

 Check the hypothesis in the image below. The table values are also there

 

 

 

Ho: mz = 39; H₁: m₂ 39
Transcribed Image Text:Ho: mz = 39; H₁: m₂ 39
α = 0.05
T(a/2, v = 2) = 4.3027
T(a/2, v = 3) = 3.1825
T(a/2, v = 4) = 2.7765
T(a/2, v = 6) = 2.4469
F(a/2, 4, 4) = 9.6045
F(a/2,3,3)= 15.4392
F(a/2,3,4)= 9.9792
F(a/2, 1,4)= 7.708
F(a/2, 4, 3) = 9.12
G(a,3,3): = 0.7977
x² = x²(2,3)= 0.2158
x² = x² (1-2, 3) =
T(α, 4) = 1.71
= 9.348
Transcribed Image Text:α = 0.05 T(a/2, v = 2) = 4.3027 T(a/2, v = 3) = 3.1825 T(a/2, v = 4) = 2.7765 T(a/2, v = 6) = 2.4469 F(a/2, 4, 4) = 9.6045 F(a/2,3,3)= 15.4392 F(a/2,3,4)= 9.9792 F(a/2, 1,4)= 7.708 F(a/2, 4, 3) = 9.12 G(a,3,3): = 0.7977 x² = x²(2,3)= 0.2158 x² = x² (1-2, 3) = T(α, 4) = 1.71 = 9.348
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Could you please check the additional hypothesis in the image below

8) Verification of a hypothesis of equality of the mathematical expectation of
two random quantities
HO: mx=my; H1: mx #my
9) Verification of a hypothesis of equality of the mathematical expectation of two
random quantities
H0: my= mz; H1: my#mz
10) Verification of a hypothesis of equality of the mathematical expectation of
two random quantities
HO: mx = mz; H1: mx #mz
11) Testing a hypothesis whether x* is a gross error. Check the maximum and
minimum values, if they are gross errors
12) Check if y* is a gross error. Check the maximum and minimum values if
they are gross errors.
Transcribed Image Text:8) Verification of a hypothesis of equality of the mathematical expectation of two random quantities HO: mx=my; H1: mx #my 9) Verification of a hypothesis of equality of the mathematical expectation of two random quantities H0: my= mz; H1: my#mz 10) Verification of a hypothesis of equality of the mathematical expectation of two random quantities HO: mx = mz; H1: mx #mz 11) Testing a hypothesis whether x* is a gross error. Check the maximum and minimum values, if they are gross errors 12) Check if y* is a gross error. Check the maximum and minimum values if they are gross errors.
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