#8 7. A block of mass m sits on the ground. A student pulls up on the block with a tension T, but theblock remains in contact with the ground. What is the normal force on the block?1775- (mg) = 0$8Fg = mg.8. Block B weighs 710 N. The coefficient of static friction betweenthe block and horizontal surface is 0.25. Calculate the maximum.weight of block A for which the system will be in equilibrium.Smax(25) (710)=177.5NT₁ must = 177.5mg21775 NmT₁=177.5N9. Picture given below shows the motion of two boxes underthe effect of applied force. Friction constant between thesurfaces is k-0.4. Find the acceleration of the boxes andtension on the rope.T+F-10m=0= 710Nm₂=1kgF₁ = mg.-TN£<>TVF₁ = 710NB10. When system is in motion, find the acceleration and the tension on the rope.می تر₂-177.50T₁mi-3kgF=20NT=?A37°12258T₁-172 17745°F=30NT

Answered: Image /qna-images/answer/0e098bc0-6ea1-4e55-ac59-f4684ce0a0b4.jpg

8. Block B weighs 710 N. The coefficient of static friction between the block and horizontal surface is 0.25. Calculate the maximum weight of block A for which the system will be in equilibrium. I mut: 127.5

8. Block B weighs 710 N. The coefficient of static friction between the block and horizontal surface is 0.25. Calculate the maximum weight of block A for which the system will be in equilibrium. I mut: 127.5

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter5: Displacement And Force In Two Dimensions

Section: Chapter Questions

Problem 81A

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Torque

Torque is the rotational equivalent of linear force in physics and mechanics. Based on the course of study, it is also known as the moment of force, rotational force, or turning effect.

Question

7. A block of mass m sits on the ground. A student pulls up on the block with a tension T, but the
block remains in contact with the ground. What is the normal force on the block?
1775- (mg) = 0
$8
Fg = mg.
8. Block B weighs 710 N. The coefficient of static friction between
the block and horizontal surface is 0.25. Calculate the maximum.
weight of block A for which the system will be in equilibrium.
Smax(25) (710)=177.5N
T₁ must = 177.5
mg21775 N
m
T₁=177.5N
9. Picture given below shows the motion of two boxes under
the effect of applied force. Friction constant between the
surfaces is k-0.4. Find the acceleration of the boxes and
tension on the rope.
T+F-10m=0
= 710N
m₂=1kg
F₁ = mg.-T
N
£<>T
VF₁ = 710N
B
10. When system is in motion, find the acceleration and the tension on the rope.
می تر
₂-177.50
T₁
mi-3kg
F=20N
T=?
A
37°
12258
T₁-172 177
45°
F=30NT

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